如何提取日期，比如说，“2016年1月16日”从正则表达式的大块文本？ [英] How do I extract the date, say, "january 16, 2016" from a large chunk of text with regex?

问题描述

我正在使用着名的OCR库从我的扫描仪中取出一些账单。它非常好，并将它找到的所有文本作为一个填充了OCR文本的大字符串返回。



在账单顶部附近，有一条线那说

Hi,

I am OCRing some bills from my scanner with a well-known OCR library. It's very good, and returns all the text it finds as a big string filled with the OCR'd text.

Near the top of the bill, there is a line that says

January 16, 2016

我尝试将输出拆分成行，但是每个帐单的行不同，总是在相同的< long month>，< day number>，< four-digit ye​​ar>格式。



什么是正则表达式我可以用来咀嚼文本，并选择那种格式的日期？



我尝试了什么：



我谷歌搜索和搜索但我可能没有使用正确的搜索。任何提示都会有所帮助！

I have tried splitting the output into lines, but it's on a different line for each bill, always in the same <long month>, <day number>, <four-digit year> format.

What is a Regex I can use to munch on the text, and pick out the date in that format?

What I have tried:

I've google searched and searched but I am probably not using the right searches. Any tips would help!

推荐答案

首先，抓住Expresso的副本。

你的正则表达式可能会像

/ January | February | .... | December\s * \d {1,2} \ * *，\ s * \d {4} /

我已经抛入 \s * s，因此它可以容忍可变数量的空白（根据我对OCR的体验。

随意随意咀嚼这个。



编辑：oops！删除虚假[]



edit2：更正了E x的拼写 presso

First thing, grab a copy of Expresso.
Your regex will probably wind up something like
/January|February|....|December\s*\d{1,2}\s*,\s*\d{4}/
I've thrown in the \s*s so it will be tolerant of variable amounts of whitespace (from my experience of OCR).
Feel free to munch this up however you like.

edit: oops! removed spurious []

edit2: corrected spelling of Expresso

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