正则表达式提取方括号之间的文本 [英] Regular expression to extract text between square brackets

问题描述

简单的正则表达式问题.我有以下格式的字符串:

Simple regex question. I have a string on the following format:

this is a [sample] string with [some] special words. [another one]

提取方括号内单词的正则表达式是什么，即.

What is the regular expression to extract the words within the square brackets, ie.

sample
some
another one

注意:在我的用例中，括号不能嵌套.

Note: In my use case, brackets cannot be nested.

推荐答案

您可以全局使用以下正则表达式:

You can use the following regex globally:

[(.*?)]

说明:

• [ : [ 是一个元字符，如果要按字面意思匹配，则需要对其进行转义.
• (.*?) :以非贪婪的方式匹配所有内容并捕获它.
• ] : ] 是一个元字符，如果要按字面意思匹配，则需要对其进行转义.

• [ : [ is a meta char and needs to be escaped if you want to match it literally.
• (.*?) : match everything in a non-greedy way and capture it.
• ] : ] is a meta char and needs to be escaped if you want to match it literally.

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