使用正则表达式捕获方括号内的文本 [英] Capture the text inside square brackets using a regex

问题描述

我在这里看到了问题:正则表达式捕获{}这与我想要的类似，但我无法让它工作.

I saw question here: Regex to capture {} which is similar to what I want, but I cannot get it to work.

我的数据是:

[Honda] Japanese manufacturer [VTEC] Name of electronic lift control

我希望输出是

[Honda], [VTEC]

我的表达是:

m = re.match('(\[[^\[\]]*\])', '[Honda] Japanese manufacturer [VTEC] Name of electronic lift control')

我希望:

• m.group(0) 输出[Honda]
• m.group(1) 输出[VTEC]

• m.group(0) to output [Honda]
• m.group(1) to output [VTEC]

然而两者都输出[Honda].如何访问第二场比赛?

However both output [Honda]. How can I access the second match?

推荐答案

您可以使用 re.findall 来获取所有匹配项，尽管您会在列表中获取它们，但您不会'不需要捕获组:

You can use re.findall to get all the matches, though you'll get them in a list, and you don't need capture groups:

m = re.findall('\[[^\[\]]*\]', '[Honda] Japanese manufacturer [VTEC] Name of electronic lift control')

给出 ['[Honda]', '[VTEC]'] 所以你可以得到每一个:

Gives ['[Honda]', '[VTEC]'] so you can get each with:

print(m[0])
# => [Honda]

print(m[1])
# => [VTEC]

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