C程序根据计数打印字符数 [英] C program to print number of characters as per the count
问题描述
您是数据字符串的编码形式，如下所示：连续
出现的字母（最多9个）由字母
后跟数字表示发生。
例如，字符串
a9a3b2c4de
代表字符串
aaaaaaaaaaaabbccccdc
- 即连续12次a的出现次数，然后是2 bs，然后是
4 cs，然后是广告，最后是c
给定一个编码的表格，你必须输出数据字符串。
如果条件不进入两个
整理，添加代码块，缩进排序，删除虚假空行 - OriginalGriff [/ edit]
我尝试过什么：
You are the encoded form of a data string as follows: consecutive
occurrences of a letter (up to 9) are represented by the letter
followed by the number of occurrences.
For example, the string
a9a3b2c4de
stands for the string
aaaaaaaaaaaabbccccdc
- that is, 12 consecutive occurrences of a, followed by 2 bs, and then
4 cs, followed by a d and finally c
Given an encoded form, you have to output the data string.
Its not entering the two if conditions
[edit]Tidy up, code block added, indentation sorted, spurious blank lines removed - OriginalGriff[/edit]
What I have tried:
#include<stdio.h>
int main()
{
int i,n,s;
char a[100];
scanf("%d",&s);
for(i=0;i<s;i++)
{
scanf("%c",&a[i]);
}
for(i=0;i<s;i++)
{
if((a[i]>='a' && a[i]<='z')&&(a[i+1]>='a'&& a[i+1]<='z'))
{
printf("%c",a[i]);
}
else if((a[i]>='a' && a[i]<='z') &&(a[i+1]>='2' && a[i+1]<='9'))
{
n=a[i+1];
while(n>0)
{
printf("%c",a[i]);
n=n-1;
}
}
}
if(a[s-1]>='a'&& a[s-1]<='z')
{
printf("%c",a[s-1]);
}
return 0;
}
推荐答案
我为你缩进了代码，所以它更容易阅读。
但是......编译并不意味着你的代码是正确的！ ：笑：
将开发过程想象成编写电子邮件：成功编译意味着您使用正确的语言编写电子邮件 - 例如英语而不是德语 - 而不是电子邮件包含您的邮件想发送。
所以现在你进入第二阶段的发展（实际上它是第四或第五阶段，但你将在之后的阶段进入）：测试和调试。
首先查看它的作用，以及它与你想要的有何不同。这很重要，因为它可以为您提供有关其原因的信息。例如，如果程序旨在让用户输入一个数字并将其翻倍并打印答案，那么如果输入/输出是这样的：
I've indented you code for you, so it's easier to read.
But ... Compiling does not mean your code is right! :laugh:
Think of the development process as writing an email: compiling successfully means that you wrote the email in the right language - English, rather than German for example - not that the email contained the message you wanted to send.
So now you enter the second stage of development (in reality it's the fourth or fifth, but you'll come to the earlier stages later): Testing and Debugging.
Start by looking at what it does do, and how that differs from what you wanted. This is important, because it give you information as to why it's doing it. For example, if a program is intended to let the user enter a number and it doubles it and prints the answer, then if the input / output was like this:
Input Expected output Actual output
1 2 1
2 4 4
3 6 9
4 8 16然后很明显问题出在将它加倍的位 - 它不会将自身加到自身上，或者将它乘以2，它会将它自身相乘并返回输入的平方。
所以，你可以查看代码和很明显，它在某处：
Then it's fairly obvious that the problem is with the bit which doubles it - it's not adding itself to itself, or multiplying it by 2, it's multiplying it by itself and returning the square of the input.
So with that, you can look at the code and it's obvious that it's somewhere here:
int Double(int value)
{
return value * value;
}
一旦你知道可能出现的问题，就开始使用teh调试器找出原因。在你的行上设一个断点：
Once you have an idea what might be going wrong, start using teh debugger to find out why. Put a breakpoint on your line:
myaverage.DisplayAverage();
并运行你的应用程序。在执行代码之前，请考虑代码中的每一行应该做什么，并将其与使用Step over按钮依次执行每一行时实际执行的操作进行比较。它符合您的期望吗？如果是这样，请转到下一行。
如果没有，为什么不呢？它有何不同？
这是一项非常值得开发的技能，因为它可以帮助你在现实世界和发展中。和所有技能一样，它只能通过使用来改善！
是的，我可能会告诉你问题是什么 - 但这并不难做到，并且你将同时学到一些非常有价值的东西！
首先，确切了解循环开始时会发生什么：变量的值是多少。 （相信我，这是一个非常大的暗示！）
and run your app. Think about what each line in the code should do before you execute it, and compare that to what it actually did when you use the "Step over" button to execute each line in turn. Did it do what you expect? If so, move on to the next line.
If not, why not? How does it differ?
This is a skill, and it's one which is well worth developing as it helps you in the real world as well as in development. And like all skills, it only improves by use!
Yes, I could probably tell you what "the problem" is - but it's not difficult to do this yourself, and you will learn something really worthwhile at the same time!
Start by following exactly what happens when your loops begin: what are the values of the variables. (Trust me, that's a pretty big hint!)
你的代码有两个问题（至少:-)）。
Thre are (at least :-) ) two problems with you code.
- 在
scanf中悬挂换行符（例如，参见如何在阅读单字符用户输入时避免悬空换行 [ ^ ]） - 对读数字的错误解释：如果您阅读
' 4'然后你必须重复（'4' - '0'）次
- Dangling newline character in
scanf(see, for instance How do I avoid a "dangling" newline when reading single character user input[^]) - Wrong interpretation of the read digit: if you read
'4'then you have to repeat('4'-'0')times
尝试
Try
#include <stdio.h>
int main()
{
int i,n,s;
char a[100];
scanf("%d",&s);
for(i=0;i<s;i++)
{
scanf(" %c",&a[i]);
}
for(i=0;i<s;i++)
{
if((a[i]>='a' && a[i]<='z')&&(a[i+1]>='a'&& a[i+1]<='z'))
{
printf("%c",a[i]);
}
else if((a[i]>='a' && a[i]<='z') &&(a[i+1]>='2' && a[i+1]<='9'))
{
n=a[i+1]-'0';
while(n>0)
{
printf("%c",a[i]);
n=n-1;
}
}
}
if(a[s-1]>='a'&& a[s-1]<='z')
{
printf("%c",a[s-1]);
}
printf("\n");
return 0;
}
建议学会正确缩进代码，这有助于阅读。看看你的问题。
程序员的编辑有这样的功能。
Notepad ++ Home [ ^ ]
ultraedit [ ^ ]
您的练习是关于游程编码 - 维基百科 [ ^ ]。 />
因为您正在处理职位i和i + 1，你需要提前1步停止循环。
Advice learn to indent properly your code, it helps reading. See your question.
Programmer's editors have this kind of features.
Notepad++ Home[^]
ultraedit[^]
Your exercise is about Run-length encoding - Wikipedia[^].
Since you are working with positionsiandi+1, you need to stop the loop 1 step earlier.
它没有输入两个如果条件
Its not entering the two if conditions
当你不明白为什么你的代码没有达到预期效果时，答案是调试器
有一个工具可以让你看到你的代码在做什么，它的名字是调试器。它也是一个很好的学习工具，因为它向你展示了现实，你可以看到哪种期望与现实相符。
当你不明白你的代码在做什么或为什么它做它做的时候，答案就是答案是调试器。
使用调试器查看代码正在执行的操作。只需设置断点并查看代码执行情况，调试器允许您逐行执行第1行并在执行时检查变量。
调试器 - 维基百科，免费的百科全书 [ ^ ]
掌握Visual Studio 2010中的调试 - 初学者指南 [ ^ ]
使用Visual Studio 2010进行基本调试 - YouTube [ ^ ]
调试器在这里向您展示您的代码正在做什么，您的任务是与什么进行比较应该这样做。
调试器中没有魔法，它没有找到错误，它只是帮助你。当代码没有达到预期的效果时，你就会接近一个错误。
When you don't understand why your code don't do what you expect, the answer is debugger
There is a tool that allow you to see what your code is doing, its name is debugger. It is also a great learning tool because it show you reality and you can see which expectation match reality.
When you don't understand what your code is doing or why it does what it does, the answer is debugger.
Use the debugger to see what your code is doing. Just set a breakpoint and see your code performing, the debugger allow you to execute lines 1 by 1 and to inspect variables as it execute.
Debugger - Wikipedia, the free encyclopedia[^]
Mastering Debugging in Visual Studio 2010 - A Beginner's Guide[^]
Basic Debugging with Visual Studio 2010 - YouTube[^]
The debugger is here to show you what your code is doing and your task is to compare with what it should do.
There is no magic in the debugger, it don't find bugs, it just help you to. When the code don't do what is expected, you are close to a bug.
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