如果窗口弹出 [英] if window is popup

问题描述

有没有办法确定当前窗口是否是弹出窗口？这就是我现在所拥有的，但由于某种原因，它不起作用。我试图确保某些页面只显示在弹出窗口中。

Is there a way to determine if the current window is a popup? This is what I have right now but for some reason it is not working. I am trying to make sure that certain pages are only shown in popup window.

if(!opener)
window.location = 'error.php';

即使窗口没有弹出窗口，opener的值也是[object DOMWindow]。

The value of opener is [object DOMWindow] even though the window is not popup.

推荐答案

假设你自己打开弹出窗口 - 设置一个标志：

Assuming you're opening popup windows yourself- set a flag:

var myWindow = window.open(...);
myWindow.isPopup = true;

然后，在弹出窗口中，检查标志：

then, in your popup window, check for the flag:

if (!window.isPopup) {
    window.location = 'error.php';
}

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