关于弹出窗口 [英] regarding popup window

问题描述

我有两个文本框，如果在两个texbox中都插入了值，那么它应该显示一个弹出窗口，因为如果任何一个文本框为空，则成功插入数据然后它应该显示一个弹出窗口，因为数据未成功插入。 ..... plz帮我任何人

i had two textboxes if in both texboxes values are inserted then it should display a popup window as your data inserted succesfully if any one of the textbox is empty then it should display a pop window as data not inserted successfully.......plz help me anyone

推荐答案

你不想要使用AJAX，这很好，但你不想也使用Javascript？我想你已经去了javascript以显示通知提醒消息。但是这条消息你也可以从后面的代码中显示出来。请查看以下内容：

Hi,

you don't want to use AJAX, that is fine, but you don't want to use Javascript also ? I think you have go for javascript in order to show the notification alert message. but this message you can show from code behind also. check out below how:

ScriptManager.RegisterClientScriptBlock(this, this.GetType(), "Notify", "alert('Data Inserted Successfully');", true);

您可以根据条件更改消息文本。



参考 ScriptManager.RegisterStartupScript方法（页面，类型，字符串，字符串，布尔值） [ ^ ]了解更多信息。



希望它有所帮助。

you can change the message text however you need based on the conditions.

refer ScriptManager.RegisterStartupScript Method (Page, Type, String, String, Boolean)[^] for more.

hope it helps.

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