javascript正则表达式替换括号之间的空格 [英] javascript regex replace spaces between brackets

问题描述

如果在括号之间，我如何使用JS正则表达式替换空格的所有出现？
所以，我想要的是：

How can I use JS regex to replace all occurences of a space with the word SPACE, if between brackets? So, what I want is this:

myString = "a scentence (another scentence between brackets)"
myReplacedString = myString.replace(/*some regex*/)
//myReplacedString is now "a scentence (anotherSPACEscentenceSPACEbetweenSPACEbrackets)"

编辑：
我试过的是这个（我对正则表达式来说很新）

what I've tried is this (I'm quite new to regular expressions)

myReplacedString = myString.replace(/\(\s\)/, "SPACE");

推荐答案

您可以使用正则表达式：

You could perhaps use the regex:

/\s(?![^)]*\()/g

这将匹配任何空格，前面没有开口括号，空格和开口括号之间没有右边括号。

This will match any space without an opening bracket ahead of it, with no closing bracket in between the space and the opening bracket.

这是一个演示。

编辑：我没有考虑句子不以括号结尾的情况。然而，@ thg435的正则表达式涵盖了它：

I hadn't considered cases where the sentences don't end with brackets. The regexp of @thg435 covers it, however:

/\s(?![^)]*(\(|$))/g

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