Javascript正则表达式删除空格 [英] Javascript Regular Expression Remove Spaces

问题描述

所以我正在为JQuery编写一个小插件来删除字符串中的空格。 查看此处

So i'm writing a tiny little plugin for JQuery to remove spaces from a string. see here

(function($) {
    $.stripSpaces = function(str) {
        var reg = new RegExp("[ ]+","g");
        return str.replace(reg,"");
    }
})(jQuery);

我的正则表达式目前是 [] + 收集所有空间。
这个有效..但是它不会让我的口味很好..
我也试过 [\ s] + 和 [\ W] + 但都没有工作..

my regular expression is currently [ ]+ to collect all spaces. This works.. however It doesn't leave a good taste in my mouth.. I also tried [\s]+ and [\W]+ but neither worked..

必须有一个更好（更简洁）的方式只搜索空格。

There has to be a better (more concise) way of searching for only spaces.

推荐答案

我建议您使用文字符号，并使用 \s 字符类：

I would recommend you to use the literal notation, and using the \s character class:

//..
return str.replace(/\s/g, '');
//..

使用字符类 \s 只需''，这将匹配更多的空白字符，例如' \\\\ n 等..，寻找''将只替换ASCII 32空格。

There's a difference between using the character class \s and just ' ', this will match a lot of more white-space characters, for example '\t\r\n' etc.., looking for ' ' will replace only the ASCII 32 blank space.

当你想构建动态模式时， RegExp 构造函数很有用，在这种情况下你不需要它。

The RegExp constructor is useful when you want to build a dynamic pattern, in this case you don't need it.

此外，如你所说，[\ s] + didn'使用 RegExp 构造函数，这是因为你传递一个字符串，你应该双重转义反斜杠，否则它们将被解释为内部的字符转义string（例如：\ s===s（未知逃脱））。

Moreover, as you said, "[\s]+" didn't worked with the RegExp constructor, that's because you are passing a string, and you should "double escape" the back-slashes, otherwise they will be interpreted as character escapes inside the string (e.g.: "\s" === "s" (unknown escape)).

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