正则表达式删除每行开头的空格? [英] Regular expression to remove space in the beginning of each line?
问题描述
我想删除每行开头的空格。
I want to remove space in the beggining of each line.
我在每行中都有数据,开头有一组空格,所以数据出现在中间,我想删除每行开头的空格。
I have data in each line with a set of spaces in the beginning so data appears in the middle, I want to remove spaces in the beginning of each line.
tmp = tmp.replace(/(<([^>]+)>)/g,"")
如何添加 ^ \s
条件为 replace()
?
推荐答案
删除所有前导空格:
str = str.replace(/^ +/gm, '');
正则表达式非常简单 - 一开始就有一个或多个空格。更有趣的是标志 - / g
(全局)来替换所有匹配而不仅仅是第一个,而 / m
(multiline)使插入符号与每行的开头匹配,而不仅仅是字符串的开头。
The regex is quite simple - one or more spaces at the start. The more interesting bits are the flags - /g
(global) to replace all matches and not just the first, and /m
(multiline) so that the caret matches the beginning of each line, and not just the beginning of the string.
工作示例: http://jsbin.com/oyeci4
Working example: http://jsbin.com/oyeci4
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