正则表达式删除序数 [英] regex to remove ordinals

问题描述

我需要通过正则表达式删除序数，但我的正则表达式技能非常缺乏.以下内容定位序数，但包括返回值中的前面的数字.我只需要隔离和删除序数.

I need to remove ordinals via regex, but my regex skills are quite lacking. The following locates the ordinals, but includes the digit just prior in the return value. I need to isolate and remove just the ordinal.

[0-9](?:st|nd|rd|th)

推荐答案

您需要使用 后视断言 以便只匹配[0-9] 前面的st|nd|rd|th，但>[0-9] 不包含在匹配中.即:

You need to use a look-behind assertion so that only st|nd|rd|th preceded by a [0-9] are matched, but the [0-9] isn't included in the match. i.e.:

(?<=[0-9])(?:st|nd|rd|th)

我已链接到与 perl 兼容的语法，但如果您使用的是 posix、posix 扩展、vi 或许多其他正则表达式语法之一，则您需要查找语法.

I've linked to the perl-compatible syntax, but if you're using posix, posix extended, vi or one of many other regex syntaxes you'll need to look up the syntax.

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