Javascript回调两个函数 [英] Javascript callback for two functions

问题描述

有没有办法用Javascript（ES6）实现代码？

Is there a way to achieve the code bellow with Javascript (ES6)?

如果是，我该怎么办？我试试这个例子，但它没有用。

If yes, how can I do it? I try this example, but it didn't work.

const funcA = (callback, arg1) => {
  console.log("Print arg1: " + arg1); /* Print arg1: argument1 */
  let x = 0;
  x = callback(x, );
  return x;
}

const funcB = (x, prefix) => {
  console.log("Print prefix: " + prefix); /* Print prefix: PREFIX_ */
  x = x + 1;
  return x;
}

/* Exec function funcA */
let x = funcA(funcB( ,"PREFIX_"), "argument1");
console.log("Value of x: " + x); /* Value of x: 1 */

推荐答案

部分申请在js中还不可能。你需要另一个箭头函数作为回调函数：

Partial application is not yet possible in js. You need another arrow function that acts as a callback:

funcA(x => funcB(x ,"PREFIX_"), "argument1");

要打电话说你不需要额外的逗号：

To call that you don't need that extra comma:

x = callback(x)

当此提案可能允许写下此内容时：

Somewhen this proposal might allow to write this:

 funcA( funcB(?, "PREFIX_"), "argument1")

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