在node.js中，如何以最轻量级的方式检查给定的代码字符串在语法上是否正确？ [英] In node.js, How do you check whether a given string of code is syntactically correct in the most lightweight way?

问题描述

想象一下，我接受来自用户的一段代码，并且想要检查给定的字符串是否是有效的JS？仅从语法角度来看。

Imagine that I accept a piece of code from a user and want to just check whether the given string is a valid JS or not? Just from the syntax perspective.

function checkCode(x){
// Logic

}
// returns a boolean, whether 'x' is syntactically right or wrong.

我不希望解决方案 eval ，因为当给定代码'x'在语法错误时整个nodejs进程都会出现语法错误。

I don't want solutions with eval, since the whole nodejs process gets in to a syntax error when the given code, 'x' is syntactically wrong.

推荐答案

不要使用 eval ，这与将服务器的控制权移交给公共互联网完全相同。任何人都可以对您的服务器做任何事情 - 删除文件，泄漏文件，发送垃圾邮件等等。令我感到震惊的是，当我注意到它时，答案已收到3个upvotes。

Don't use eval that is literally the same as handing over the control of your server to the public internet. Anyone can do anything with your server - delete files, leak files, send spam email and so on. I am shocked that the answer had received 3 upvotes by the time I noticed it.

只需使用像esprima这样的Javascript解析器 http://esprima.org/

Just use a Javascript parser like esprima http://esprima.org/

这是一个语法验证器示例，它甚至可以收集多个错误：< a href =https://github.com/ariya/esprima/blob/master/demo/validate.js#L21-L41\"rel =noreferrer> https://github.com/ariya/esprima/blob/ master / demo / validate.js＃L21-L41

Here is a syntax validator example it can even collect multiple errors: https://github.com/ariya/esprima/blob/master/demo/validate.js#L21-L41

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