轻量级的Scala fork连接语法 [英] A light weight Scala fork join syntax

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问题描述

尽管即将推出Java 7标准fork/join框架,但我正在构建一些帮助程序方法,该方法的语法轻巧,可以让客户端并行运行代码. 这是一个可运行的主要方法来说明这个想法.

Despite the upcoming java 7 standard fork/join framework, I am building some helper method that is light weight in syntax for client to run code in parallel. Here is a runnable main method to illustrate the idea.

import actors.Futures

object ForkTest2 {



  def main(args: Array[String]) {
    test1
    test2
  }



  def test1 {
    val (a, b, c) =fork({
      Thread.sleep(500)
      println("inside fx1 ",+System.currentTimeMillis)
      true
    }, {
      Thread.sleep(1000)
      println("inside fx2 ",+System.currentTimeMillis)
      "stringResult"
    }, {
      Thread.sleep(1500)
      println("inside fx3 ",+System.currentTimeMillis)
      1
    })

    println(b, a, c)
    true
  }

  def test2 {
    val results = forkAll({
      () =>
              Thread.sleep(500)
              println("inside fx1 ",+System.currentTimeMillis)
              true
    }, {
      () =>
              Thread.sleep(1000)
              println("inside fx2 ",+System.currentTimeMillis)
              "stringResult"
    }, {
      () =>
              Thread.sleep(1500)
              println("inside fx3 ",+System.currentTimeMillis)
              1
    }, {
      () =>
              Thread.sleep(2000)
              println("inside fx4 ",+System.currentTimeMillis)
              1.023
    })

    println(results)
    true
  }

  val tenMinutes = 1000 * 60 * 10

  def fork[A, B, C](
          fx1: => A,
          fx2: => B,
          fx3: => C
          ) = {
    val re1 = Futures.future(fx1)
    val re2 = Futures.future(fx2)
    val re3 = Futures.future(fx3)
    //default wait 10 minutes
    val result = Futures.awaitAll(tenMinutes, re1, re2, re3)
    (
            result(0).asInstanceOf[Option[A]],
            result(1).asInstanceOf[Option[B]],
            result(2).asInstanceOf[Option[C]]

            )
  }

  type fxAny = () => Any

  def forkAll(
          fx1: fxAny*
          ): List[Any] = {
    val results = fx1.toList.map {fx: fxAny => Futures.future(fx())}
    Futures.awaitAll(tenMinutes, results: _*)
  }
}

输出的样本是

(inside fx1 ,1263804802301)
(inside fx2 ,1263804802801)
(inside fx3 ,1263804803301)
(Some(stringResult),Some(true),Some(1))
(inside fx1 ,1263804803818)
(inside fx2 ,1263804804318)
(inside fx3 ,1263804804818)
(inside fx4 ,1263804805318)
List(Some(true), Some(stringResult), Some(1), Some(1.023))

测试1说明了类型安全返回类型

test 1 illustrate a type safe return type

测试2说明了任意输入参数

test 2 illustrate a arbitrary input argument

我希望将两种测试方法结合起来,以便客户端代码可以与类型安全返回类型并行运行任意函数.

I hope to combine the two test method so the client code can run arbitrary function in parallel with type safe return type.

关于任意函数参数的另一点是:

Another point about the arbitrary function arguments is:

我认为这条线

  type fxAny = () => Any

应该真的是代码

  type fxAny =  => Any

,但是scala编译器不允许我这样做.

, but the scala compiler do not allow me to do so.

感谢您的帮助.

推荐答案

Eric Torreborre在@retronym提供的链接中写道:

Eric Torreborre wrote in the link provided by @retronym:

trait LazyParameters { 
  /** transform a value to a zero-arg function returning that value */ 
  implicit def toLazyParameter[T](value: =>T) = new LazyParameter(() => value) 
  /** class holding a value to be evaluated lazily */ 
  class LazyParameter[T](value: ()=>T) { 
    lazy val v = value() 
    def apply() = v 
  } 
} 

这是您的测试的LazyParameter版本:

Here's LazyParameter version of your test:

object ForkTest2 extends LazyParameters {

...

def forkAll(fx1: LazyParameter[Any]*): List[Any] = {
  val results = fx1.toList.map {
    fx: LazyParameter[Any] => Futures.future(fx.apply())}
  Futures.awaitAll(tenMinutes, results: _*)
}

编辑:您已经注意到,隐式评估by-name参数,并且不会延续评估延迟.为什么不只使用future一词呢?我个人认为这会使代码更具可读性.

Edit: As you've noticed, implicit evaluates the by-name parameter and it doesn't carry forward the evaluation delay. Why not just use the word future? I personally think it makes the code more readable.

import actors.Futures
import actors.Futures.future
import actors.Future

...

def test2 {
  val results = forkAll(
    future {
      Thread.sleep(500)
      println("inside fx1 ",+System.currentTimeMillis)
      true
    },
    future {
      Thread.sleep(1000)
      println("inside fx2 ",+System.currentTimeMillis)
      "stringResult"
    },
    future {
      Thread.sleep(1500)
      println("inside fx3 ",+System.currentTimeMillis)
      1
    },
    future {
      Thread.sleep(2000)
      println("inside fx4 ",+System.currentTimeMillis)
      1.023
    })

  println(results)
  true
}

...

def forkAll(futures: Future[Any]*): List[Any] = {
  println("forkAll")
  Futures.awaitAll(tenMinutes, futures: _*)
}

这篇关于轻量级的Scala fork连接语法的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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