错误的随机数的Android [英] Bug in random numbers in Android
本文介绍了错误的随机数的Android的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
TreeSet myNumbers = new TreeSet();
Random randGen = new Random();
for (int i = 1; i <= 16; i++) {
// number generation here
int randNum = randGen.nextInt(16 - 1) + 1;
for (;;) {
if (myNumbers.add(randNum))
break;
else
randNum = randGen.nextInt();
}
Toast.makeText(getApplicationContext(), "" + randNum, 100).show();
}
我要生成1和16相同的数量应该不重复的随机数。
I want to generate random numbers between 1 and 16 and the same number should not be repeated.
在code以上给了我这样的输出:
The code above gives me output like:
2, 5, 7, 9, 1, 4, 10.4109446, -448831, 98824724, 11, 13, ...
我不知道为什么它给我的随机数不在1-16范围内,请帮助我。
I do not know why it gives me random numbers not in the 1-16 range, please help me out.
推荐答案
要生成一个范围内的随机数,它是这样的:
To generate a random number in a range, it is like:
int min = ...
int max = ...
int randNumber = min + new Random().nextInt(max - min + 1);
所以,在你的榜样,你想生成[1,16]一个随机数,它看起来像:
So in your example where you want to generate a random number from [1, 16], it would look like:
int randNumber = 1 + new Random().nextInt(16 - 1 + 1);
或者,如果你选择简化:
Or if you choose to simplify:
int randNumber = 1 + new Random().nextInt(16);
另外,你真的应该使用,而
循环而不是无限为
循环:
Also, you should really be using a while
loop instead of an infinite for
loop:
final TreeSet<Integer> myNumbers = new TreeSet<>();
final Random rand = new Random();
for(int i = 0; i < 16; i++){
int n = 1 + rand.nextInt(16);
while(!myNumbers.add(n))
n = 1 + rand.nextInt(16);
}
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