如何输入两年并在它们之间显示两年？ [英] How to input two years and display the leapyear between them?

问题描述

我们想进入两年并从中找到闰年



我尝试过：

we want to enter two years and find the leap year from that

What I have tried:

#include <iostream>
using namespacestd;
int main()

推荐答案

引用：

我们想进入两年并从中找到闰年

we want to enter two years and find the leap year from that

尝试解决问题一张纸和一支铅笔，你的程序将使用相同的原则。



我们不做你的HomeWork。

HomeWork未设置为在乞求其他人做你的工作时测试你的技能，它会让你思考并帮助你的老师检查你对你所学课程的理解以及你应用它们时遇到的问题。

你的任何失败都会帮助你的老师发现你的弱点并设定补救措施。

所以，试一试，重读你的课程并开始工作。如果您遇到特定问题，请显示您的代码并解释这个问题，我们可能会提供帮助。



作为程序员，您的工作是创建算法解决特定问题，你不能依赖别人永远为你做，所以有一段时间你必须学会​​如何。而且越快越好。

当你要求解决方案时，就像试图通过培训其他人来学习开车一样。

创建算法基本上是找到数学并做出必要的调整以适应你的实际问题。



发展的概念就像这个词所暗示的那样：系统地使用科学和满足特定目标或要求的技术知识。 BusinessDictionary.com [ ^ ]

这与有一个不一样快速谷歌并放弃，如果我找不到正确的代码。

Try to solve the problem with a sheet of paper and pencil, your program will use the same principle.

We do not do your HomeWork.
HomeWork is not set to test your skills at begging other people to do your work, it is set to make you think and to help your teacher to check your understanding of the courses you have taken and also the problems you have at applying them.
Any failure of you will help your teacher spot your weaknesses and set remedial actions.
So, give it a try, reread your lessons and start working. If you are stuck on a specific problem, show your code and explain this exact problem, we might help.

As programmer, your job is to create algorithms that solve specific problems and you can't rely on someone else to eternally do it for you, so there is a time where you will have to learn how to. And the sooner, the better.
When you just ask for the solution, it is like trying to learn to drive a car by having someone else training.
Creating an algorithm is basically finding the maths and make necessary adaptation to fit your actual problem.

The idea of "development" is as the word suggests: "The systematic use of scientific and technical knowledge to meet specific objectives or requirements." BusinessDictionary.com[^]
That's not the same thing as "have a quick google and give up if I can't find exactly the right code".

给定两年，你可能会发现零， 一个或许多它们之间的闰年。

在一个简单（但效率不高）的方法中，你在 start 和 end 之间进行迭代，测试跳跃（参见闰年 - 维基百科 [ ^ ]）每年都在迭代中发生。

Given two years then you may find zero, one or many leap years between them.
In a simple (yet not efficient) approach you iterate between start and end year, testing for leap (see Leap year - Wikipedia[^]) each year occurring in the iteration.

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