C ++初学者，GetAsyncKeyState麻烦，这么认为 [英] Beginner in C++, Trouble with GetAsyncKeyState, think so

问题描述

大家好。自从我完成了我的编程课程（因为我太大了，无法在大学学习），我开始自己进行实验和学习，C ++引起了我的注意。



我开始了几个月以前和我一如既往地开始尝试。所以我尝试创建一个简单的板，由'＃'表示的墙和由'+'表示的字符限制。



我开始创建电路板，二维数组板[5] [20]并做一些用于创建电路板的电路板，其中2表示墙，a 1代表玩家，0代表emty空间。

Hello there folks. Since I finished my programming course (Cause Im too young to study at university) I started experimenting and learning by myself, C++ caught my attention.

I started a few months ago and as always I started experimenting. So I tried to create a simple board limited by walls represented by '#' and a character represented by a '+'.

I started by creating the board, a bidimensional array int board[5][20] and doing some for loops that create the board with 2 representing a wall, a 1 representing the player, a 0 representing an emty space.

for(int i=0; i<=4; i++)
{
        for(int x=0; x<=19; x++)
        {
                if(i == 0 || i == 4)
                {
                     board[i][x] = 2;
                }
                else
                {
                    if(x == 0 || x == 19)
                    {
                         board[i][x] = 2;
                    }
                    else
                    {
                        board[i][x] = 0;
                    }
                }
        }
}

现在这是主循环游戏循环，我使用windows.h - GetAsyncKeyState

这样，现在因为我没有任何导师或教授指导我我不知道这个功能的分配，也许我以不支持的方式使用它。

Now this is the main loop with the game loop, Im using windows.h - GetAsyncKeyState
like this, now since I havent any tutor or professor to instruct me I dont know allot of this function, and maybe Im using it in an unpropper way.

int main()
{
    Board table(3,10);
    showGame(table);
    while(!GetAsyncKeyState(VK_ESCAPE))
    {
         showGame(table);
         if(GetAsyncKeyState(VK_UP))
         {
             table.moveUp();
         }
         if(GetAsyncKeyState(VK_DOWN))
         {
             table.moveDown();
         }
         if(GetAsyncKeyState(VK_RIGHT))
         {
             table.moveRight();
         }
         if(GetAsyncKeyState(VK_LEFT))
         {
             table.moveLeft();
         }
    }
    return 0;
}

以下是移动玩家的功能：

Here are the functions that move the player:

void Board::moveDown()
{
     int p1 = Y + 1;
     int move = board[Y][X] + board[p1][X];
     if(move == 1)
     {
             board[p1][X] = player;
             board[Y][X] = empty;
     }
}

void Board::moveUp()
{
     int p2 = Y - 1;
     int move = board[Y][X] + board[p2][X];
     if(move == 1)
     {
             board[p2][X] = player;
             board[Y][X] = empty;
     }
}

void Board::moveRight()
{
     int p3 = X + 1;
     int move = board[Y][X] + board[Y][p3];
     if(move == 1)
     {
             board[Y][p3] = player;
             board[Y][X] = empty;
     }
}

void Board::moveLeft()
{
     int p4 = X - 1;
     int move = board[Y][X] + board[Y][p4];
     if(move == 1)
     {
             board[Y][p4] = player;
             board[Y][X] = empty;
     }
}

创建电路板，与播放器一起显示。这个问题只允许我做1次移动然后它没有显示更改或它没有做到。



这是读取板的代码：< br $> b $ b

It creates the board, displays it with the player. The problem it only allows me to do 1 move then it either doesnt display the change or it doesnt do it.

And this is the code that reads the board:

system("CLS");
for(int i=0;i<=4; i++)
{
     for(int x=0;x<=19; x++)
     {
                  if(cb.board[i][x] == cb.valueWall())
                  {
                       cout << "#";
                  }
                  if(cb.board[i][x] == cb.valueEmpty())
                  {
                      cout << " ";
                  }
                  if(cb.board[i][x] == cb.valuePlayer())
                  {
                      cout << "+";
                  }
      }
      cout << "\n";
}

推荐答案

尝试在while循环中设置Sleep（）。当GetAsyncKeyState（VK_ESCAPE）返回Esc已被推送时，最好设置while（1）和break内部的情况。我不太擅长解释，但问题出在一个人需要按下按钮的时候。通过while循环，cpu需要更少的时间循环



请看这个链接

关于GetAsyncKeyState的问题

Try setting a Sleep() in the while loop . Its better to set a while(1) and a case of break inside when GetAsyncKeyState(VK_ESCAPE)returns that Esc has been pushed . I am not so good at explaining but the problem is in the time one human needs to push a button . The cpu needs a lot less time to loop though the while loop

Please see this link
Question about the "GetAsyncKeyState"

我必须添加一个更改初始变量XY的命令，因此它不是每次移动时都一样

I had to add a command that changes the initial variables XY so it werent the same every time I moved

你需要做的就是添加[

& 0x8000

。

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