将值设置为本机C ++变量时出现问题 [英] Problem in setting values to native C++ variables

问题描述

先生，我愿意为我的应用程序提供一个基本的gui，因为我选择了Win32 API。但我愿意只为GUI使用win32 API，我愿意坚持使用原生C ++的功能。



我创建了一个像这样的输入框，

Sir, I am willing to have a basic gui for my application for that I've chosen Win32 API. But I am willing to use win32 API only for GUI and I am willing to stick the functionality with native C++.

I have created an entry box like this,

entry = CreateWindow(L"EDIT", L"USE SOME INPUT HERE", WS_CHILD | WS_BORDER | WS_VISIBLE|ES_NUMBER, 0, 30, 400, 20, hWnd, (HMENU)NULL, hInst, NULL);

我愿意将在文本框中输入的值存储到整数变量。

I am willing to store this value entered in the text box to an integer variable.

SendMessage(entry,WM_GETTEXT,sizeof(buffer) / sizeof(buffer[0]),reinterpret_cast<LPARAM>(buffer));

上面的代码将输入存储到变量名称缓冲区，即LPWSTR



，我不知道如何将值转换为整数。



谢谢先生您的时间。



我的尝试：



1.添加ES_NUMBER以防止用户输入除整数之外的其他内容。



2.引用了几篇文章互联网尝试stoi，atoi并没有帮助



3.手动尝试typeconversion例如x =（int）* buffer;但这也没有帮助



请帮我这个先生

The above code will store the input to the variable name buffer which is LPWSTR

and I don't know how to get the values into an integer.

Thank you sir for your time.

What I have tried:

1. Added ES_NUMBER to prevent the user entering another thing than integer.

2. Referred several articles in the internet tried stoi, atoi and that doesn't help

3. Tried typeconversion manually e.g x = (int)*buffer; but that didn't help too

Kindly help me with this sir

推荐答案

你应该使用C函数 _wtoi [ ^ ]。

You should use the C function _wtoi[^].

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