如何在另一个文件夹中获取调试文件夹中的输出 [英] How do I obtain the output in debug folder also in another folder

问题描述

private void button35_Click_1(object sender, EventArgs e)
       {
           string str = @"C:\output\run\Ocirc.exe";
           Process process = new Process();
           process.StartInfo.FileName = str;
           process.Start();
       }

我的尝试：



这里获得的代码输出存储在debug文件夹中，但我需要在相应的文件中获取输出而不是仅调试。

What I have tried:

here in the code output obtained is stored in debug folder,but i need to obtained the output in corresponding files rather than only debug.

推荐答案

我会在网上搜索C＃Spawn流程重定向输出..有很多例子..本质上你最终会做类似的事情

I would search the net for C# Spawn process redirect output .. there are plenty of examples .. in essence you end up doing something like

process.StartInfo.UseShellExecute = false;
process.StartInfo.RedirectStandardOutput = true;
process.OutputDataReceived += (sender, args) => Console.WriteLine("received output: {0}", args.Data);
process.Start();
process.BeginOutputReadLine();

您可以用您选择的文件替换Console.WriteLine ...



您还可以通过添加来获取标准错误

where you would replace the Console.WriteLine with a write to a file of your choice ...

you can also capture standard error by adding

RedirectStandardError = true 

process.ErrorDataReceived += (sender, args) => Console.WriteLine(args.Data); 

process.BeginErrorReadLine();

此代码不是我的，顺便说一句，这要感谢Judah Himango（我曾经在这里看过一段时间的人）



这是你的另一个首发启动流程并捕获其输出（C＃）·GitHub [ ^ ]

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