二元运算符'&&'的坏操作数类型? [英] Bad operand types for binary operator '&&'..?
本文介绍了二元运算符'&&'的坏操作数类型?的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
class Divisible
{
public static void main(String args[])
{
int number[]=new int[200];
int i,sum=0;
for(i=0;i<number.length;i++)>
{
number[i]=i;
}
for(i=0;i<number.length;i++)>
{
if((number[i]>100) && (number[i]<200) && (number[i]/7))
{
sum=sum+number[i];
}
}
System.out.println("Sum =" +sum);
}
}
我的尝试:
i是java语言的新手,所以我基本上对这种类型的错误一无所知,需要做些什么......所以对我们来说是一个很大的帮助提前回答并感谢...
What I have tried:
i am new to java language so i basically don't know anything about this type of error and what needs to be done......so would be a great help to know the answer and thanks in advance...
推荐答案
(number [i] / 7)?
它不是布尔表达式而是a数值......
(number[i]/7)?
It is not a boolean expression but a numeric value...
&&是Logical AND运算符:它需要两边的布尔值。
(number [i] / 7)
不是布尔值 - 你可能意味着:
&& is the Logical AND operator: it needs boolean values on both sides.
(number[i]/7)
is not a boolean value - you probably mean something like:
if((number[i]>100) && (number[i]<200) && (number[i]/7 > 0))
问题是(number [i] / 7)
不是布尔值/逻辑值。
你需要
类似(number [i] / 7<> 0)
。
The problem is that(number[i]/7)
is not a boolean/logical value.
you need something like(number[i]/7 <> 0)
.
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