向量查询C ++疑问 [英] Vector query C++ doubt

问题描述

我有一个值为10的矢量（即ID）我还有一个矢量，它有一些字符串..



i必须找到字符串值基于id = 10.





当id为10时我应该得到字符串值形式向量。





如何做到这一点。请告诉我。



not：id不是索引



i试过我得到的价值但是我希望用迭代器....



我尝试过的事情：

i have a vector which is having value 10( i.e ID) i have one more vector which is having some string ..

i have to find the string value based on the id = 10.


when the id is 10 i should get the string value form vector.


how to do that one. please let me know.

not : id is not index

i tried i got the value but i want with iterator....

What I have tried:

for (int i(0),n(foundRowIndices3.size()); i < n; i++)
{
  if (foundRowIndices3.at(i) == nValue)
  {
	CString str = sDescription.at(i);
   }
				
}

推荐答案

为什么不使用不同的集合类型，例如< a href =https://msdn.microsoft.com/en-us/library/s44w4h2s(v=vs.100).aspx>地图类 [ ^ ]，它将值和字符串保持在一起。

Why not use a different collection type, such as the map Class[^], which keeps the value and string together.

建议：回到C / C ++基础。

C编程语言 - 维基百科，免费的百科全书 [ ^ ]

https://hassanolity.files.wordpress.com/2013/ 11 / the_c_programming_language_2.pdf [ ^ ]

http://www.ime.usp.br/~pf/Kernighan-Ritchie/C-Programming-Ebook.pdf [ ^ ]



你不掌握循环的最基本语法。

看起来他们设法发明了一种更奇怪的语法。

所以 i = 0 太简单了，他们通过使用函数调用语法 i（0）来设法进行模糊处理吗？ />
他们让我参与了这个。

Advice: go back to C/C++ basics.
The C Programming Language - Wikipedia, the free encyclopedia[^]
https://hassanolity.files.wordpress.com/2013/11/the_c_programming_language_2.pdf[^]
http://www.ime.usp.br/~pf/Kernighan-Ritchie/C-Programming-Ebook.pdf[^]

You do not master to most basic syntax for the loop.
Looks they manage to invent an even weirder syntax.
So i=0 was too simple and they managed to obfuscate by using the function calling syntax i(0) to do the same ?
They got me on this one.

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