如何将该程序转换为C ++？ [英] How to convert this program into C++?
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问题描述
#include<stdio.h>
#include<conio.h>
#include<string.h>
#include<stdlib.h>
#include<windows.h>
struct person
{
char name[35];
char address[50];
char father_name[35];
char mother_name[30];
long int mble_no;
char sex[8];
char mail[100];
char citision_no[20];
};
void menu();
void got();
void start();
void back();
void addrecord();
void listrecord();
void modifyrecord();
void deleterecord();
void searchrecord();
int main()
{
system("color 5f");
start();
return 0;
}
void back()
{
start();
}
void start()
{
menu();
}
void menu()
{
system("cls");
printf("\t\t**********WELCOME TO PHONEBOOK*************");
printf("\n\n\t\t\t MENU\t\t\n\n");
printf("\t1.Add New \t2.List \t3.Exit \n\t4.Modify \t5.Search\t6.Delete");
switch(getch())
{
case '1':
addrecord();
break;
case '2': listrecord();
break;
case '3': exit(0);
break;
case '4': modifyrecord();
break;
case '5': searchrecord();
break;
case '6': deleterecord();
break;
default:
system("cls");
printf("\nEnter 1 to 6 only");
printf("\n Enter any key");
getch();
menu();
}
}
void addrecord()
{
system("cls");
FILE *f;
struct person p;
f=fopen("project","ab+");
printf("\n Enter name: ");
got(p.name);
printf("\nEnter the address: ");
got(p.address);
printf("\nEnter father name: ");
got(p.father_name);
printf("\nEnter mother name: ");
got(p.mother_name);
printf("\nEnter phone no.:");
scanf("%ld",&p.mble_no);
printf("Enter sex:");
got(p.sex);
printf("\nEnter e-mail:");
got(p.mail);
printf("\nEnter citizen no:");
got(p.citision_no);
fwrite(&p,sizeof(p),1,f);
fflush(stdin);
printf("\nrecord saved");
fclose(f);
printf("\n\nEnter any key");
getch();
system("cls");
menu();
}
void listrecord()
{
struct person p;
FILE *f;
f=fopen("project","rb");
if(f==NULL)
{
printf("\nfile opening error in listing :");
exit(1);
}
while(fread(&p,sizeof(p),1,f)==1)
{
printf("\n\n\n YOUR RECORD IS\n\n ");
printf("\nName=%s\nAdress=%s\nFather name=%s\nMother name=%s\nMobile no=%ld\nSex=%s\nE-mail=%s\nCitizen no=%s",p.name,p.address,p.father_name,p.mother_name,p.mble_no,p.sex,p.mail,p.citision_no);
getch();
system("cls");
}
fclose(f);
printf("\n Enter any key");
getch();
system("cls");
menu();
}
void searchrecord()
{
struct person p;
FILE *f;
char name[100];
f=fopen("project","rb");
if(f==NULL)
{
printf("\n error in opening\a\a\a\a");
exit(1);
}
printf("\nEnter name of person to search\n");
got(name);
while(fread(&p,sizeof(p),1,f)==1)
{
if(strcmp(p.name,name)==0)
{
printf("\n\tDetail Information About %s",name);
printf("\nName:%s\naddress:%s\nFather name:%s\nMother name:%s\nMobile no:%ld\nsex:%s\nE-mail:%s\nCitision no:%s",p.name,p.address,p.father_name,p.mother_name,p.mble_no,p.sex,p.mail,p.citision_no);
}
else
printf("file not found");
}
fclose(f);
printf("\n Enter any key");
getch();
system("cls");
menu();
}
void deleterecord()
{
struct person p;
FILE *f,*ft;
int flag;
char name[100];
f=fopen("project","rb");
if(f==NULL)
{
printf("CONTACT'S DATA NOT ADDED YET.");
}
else
{
ft=fopen("temp","wb+");
if(ft==NULL)
printf("file opaning error");
else
{
printf("Enter CONTACT'S NAME:");
got(name);
fflush(stdin);
while(fread(&p,sizeof(p),1,f)==1)
{
if(strcmp(p.name,name)!=0)
fwrite(&p,sizeof(p),1,ft);
if(strcmp(p.name,name)==0)
flag=1;
}
fclose(f);
fclose(ft);
if(flag!=1)
{
printf("NO CONACT'S RECORD TO DELETE.");
remove("temp.txt");
}
else
{
remove("project");
rename("temp.txt","project");
printf("RECORD DELETED SUCCESSFULLY.");
}
}
}
printf("\n Enter any key");
getch();
system("cls");
menu();
}
void modifyrecord()
{
int c;
FILE *f;
int flag=0;
struct person p,s;
char name[50];
f=fopen("project","rb+");
if(f==NULL)
{
printf("CONTACT'S DATA NOT ADDED YET.");
exit(1);
}
else
{
system("cls");
printf("\nEnter CONTACT'S NAME TO MODIFY:\n");
got(name);
while(fread(&p,sizeof(p),1,f)==1)
{
if(strcmp(name,p.name)==0)
{
printf("\n Enter name:");
got(s.name);
printf("\nEnter the address:");
got(s.address);
printf("\nEnter father name:");
got(s.father_name);
printf("\nEnter mother name:");
got(s.mother_name);
printf("\nEnter phone no:");
scanf("%ld",&s.mble_no);
printf("\nEnter sex:");
got(s.sex);
printf("\nEnter e-mail:");
got(s.mail);
printf("\nEnter citizen no\n");
got(s.citision_no);
fseek(f,-sizeof(p),SEEK_CUR);
fwrite(&s,sizeof(p),1,f);
flag=1;
break;
}
fflush(stdin);
}
if(flag==1)
{
printf("\n your data id modified");
}
else
{
printf(" \n data is not found");
}
fclose(f);
}
printf("\n Enter any key");
getch();
system("cls");
menu();
}
void got(char *name)
{
int i=0,j;
char c,ch;
do
{
c=getch();
if(c!=8&&c!=13)
{
*(name+i)=c;
putch(c);
i++;
}
if(c==8)
{
if(i>0)
{
i--;
}
// printf("h");
system("cls");
for(j=0;j<i;j++)
{
ch=*(name+j);
putch(ch);
}
}
}while(c!=13);
*(name+i)='\0';
}
我的尝试：
[edit]删除上述代码（未格式化）的副本[/ edit]
What I have tried:
[edit]Duplicate of above code (unformatted) removed[/edit]
推荐答案
不要。
它已经在C中 - 这是C ++的一个子集 - 所以从技术上讲它不需要任何转换：它应该按原样运行。
但是转换C程序到C ++并不是一个好主意 - 它们并不是设计成好的C ++，因为它们根本不知道OOP原则（因为C不 有 任何OOP支持）。
更好的想法是查看它的作用，并使用它作为功能规范重写一个新的应用程序。
此外：这是垃圾代码！它没有任何理由而不是循环使用递归：
Don't.
It's already in C - which is a subset of C++ - so technically it doesn't need any conversion: it should run as it is.
But "converting" C programs to C++ isn't really a good idea - they aren't designed to be "good" C++ because they were written with no idea of OOPs principles at all (since C doesn't have any OOPs support).
A better idea would be to look at what it does, and rewrite a new application using that as a functional specification.
And besides: that's rubbish code! It's using recursion for no good reason instead of a loop:
void menu()
{
...
switch(getch())
{
case '1':
...
default:
...
menu();
}
}
它几乎没有错误检查，原作者甚至不愿意缩进它，...
我会说：如果它有效，请不要管它 - 或者正确地重写它并完全忽略该代码！
It's got little or no error checking, the original author couldn't even be bothered to indent it, ...
I'd say: if it works, leave it alone - or rewrite it properly and ignore that code completely!
这里有一些关于利用C ++改进的建议你有什么。
首先，用STL字符串替换固定字符字段。这也应该解决缓冲区溢出的问题。
Here are some suggestions on leveraging C++ to improve what you have.
First, replace the fixed character fields with STL strings. This should also fix the issue of buffer overflows.
#include <string>
struct person
{
std::string name;
std::string address;
std::string father_name;
std::string mother_name;
long int mble_no;
std::string sex;
std::string mail;
std::string citision_no;
};
上面的类（结构是一个类）只是一个POD（普通旧数据）类型。
将UI代码组织到控制台类中可能很有用。类似于：
The above class (a struct IS a class) is just a POD (plain old data) type.
It might be useful to organize your UI code into a console class. Something like:
class console
{
public:
void menu();
void got(person &);
void show(const person &);
void cls() { system("cls"); }
};
您还可以像这样抽象数据访问层或持久层：
You could also abstract your data access layer or persistence layer like so:
class persist
{
FILE *file;
public:
persist() : file(nullptr) { }
bool open(const char *path);
void addrecord(const person &);
void readrecord(person &);
void modifyrecord(person &);
void deleterecord(const person &);
void searchrecord(person &);
void close();
};
back（）和start（）函数毫无意义。考虑重写菜单功能，以便在用户选择退出选项时退出循环。
有很多空白。你的代码不需要完全遵循这个例子，但这应该给你一些想法。
The back() and start() functions were pointless. Consider rewriting the menu function to operate in a loop that exits when the user chooses a "quit" option.
There are lots of gaps. You code need not exactly follow this example but this should give you some ideas.
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