如何从Var Datavalue = Data中绑定所有记录(行) [英] How Can I Bind All Records(Rows) From Var Datavalue = Data;
本文介绍了如何从Var Datavalue = Data中绑定所有记录(行)的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
function AllcarDetails() {
$.ajax({
type: "GET",
url: "http://localhost:32359/api/CarDetails",
dataType: "json",
success: function (data) {
//alert(this.url)
var datavalue = data;
var myJsonObject = datavalue;
//alert(data["Table"][0].Voucher_No);
//debugger;
contentType: "application/json";
$.each(myJsonObject, function (i, objGet) {
$("#Cartbl").append('<table><tbody><tr><td width="50px">' + data["Table"][1].Voucher_No + '</td><td width="50px">' + data["Table"][1].Voucher_Date + '</td><td width="50px">' + data["Table"][1].VendorName + '</td>' + '<td width="50px">' + data["Table"][1].Amount + '</td></tr></tbody></table>');
});
alert('bought all data successfully');
},
error: function (xhr) {
alert(xhr.responseText);
}
});
}
ex ..如果我这样做的话(数据[表] [1]。数量)仅从sql显示第一行数据。我想绑定所有行。
ex.. if i'm put like this means (data["Table"][1].Amount) only 1st row of data is displayed from sql. i want to bind all rows.
推荐答案
.ajax({
type: 获取,
url: http:// localhost:32359 / api / CarDetails,
dataType: json,
成功: function (数据){
// alert(this.url)
var datavalue = data;
var myJsonObject = datavalue;
< span class =code-comment> // alert(data [Table] [0] .Voucher_No);
// debugger;
contentType: application / json;
.ajax({ type: "GET", url: "http://localhost:32359/api/CarDetails", dataType: "json", success: function (data) { //alert(this.url) var datavalue = data; var myJsonObject = datavalue; //alert(data["Table"][0].Voucher_No); //debugger; contentType: "application/json";
.each(myJsonObject, function (i,objGet){
.each(myJsonObject, function (i, objGet) {
( #Cartbl)。append(' < table>< tbody>< tr>< td width =50px>' + data [ 表] [ 1 ]。Voucher_No + ' < / td>< td width =50px>' + data [ 表] [ 1 ]。Voucher_Date + ' < / td>< td width =50px>' + data [ 表] [ 1 ]。VendorName + ' < / td>' + ' < span class =code-string>< td width =50px>' + data [ 表] [ 1 ]。金额+ ' < / TD>< / TR>< / tbody的>< /表>'跨度>);
});
alert(' 成功购买所有数据');
},
错误: function (xhr){
alert(xhr.responseText);
}
});
}
("#Cartbl").append('<table><tbody><tr><td width="50px">' + data["Table"][1].Voucher_No + '</td><td width="50px">' + data["Table"][1].Voucher_Date + '</td><td width="50px">' + data["Table"][1].VendorName + '</td>' + '<td width="50px">' + data["Table"][1].Amount + '</td></tr></tbody></table>'); }); alert('bought all data successfully'); }, error: function (xhr) { alert(xhr.responseText); } }); }
ex ..如果我这样做的话(数据[表] [1]。数量)仅从sql显示第一行数据。我想绑定所有行。
ex.. if i'm put like this means (data["Table"][1].Amount) only 1st row of data is displayed from sql. i want to bind all rows.
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