如何从R data.frame获取行 [英] How to get row from R data.frame
本文介绍了如何从R data.frame获取行的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
如何从数据框架中获取特定行作为列表(列标题作为列表的键)?
具体来说,我的数据框架是
ABC
1 5 4.25 4.5
2 3.5 4 2.5
3 3.25 4 4
4 4.25 4.5 2.25
5 1.5 4.5 3
我想得到一个相当于
> c(a = 5,b = 4.25,c = 4.5)
abc
5.0 4.25 4.5
解决方案
x [r,]
其中r是您感兴趣的行,请尝试这样,例如:
#Add你的数据
x< - structure(list(A = c(5,3.5,3.25,4.25,1.5),
B = c(4.25,4,4,4.5,4.5),
C = c(4.5,2.5,4,2.25,3)
),
.Names = c(A,B,C),
class = data.frame,
row.names = c(NA,-5L)
)
#矢量你的结果应该匹配
y< -c(A = 5,B = 4.25,C = 4.5)
#测试行中的项目与您想要的向量匹配
x [1,] == y
I have a data.frame with column headers.
How can I get a specific row from the data.frame as a list (with the column headers as keys for the list)?
Specifically, my data.frame is
A B C 1 5 4.25 4.5 2 3.5 4 2.5 3 3.25 4 4 4 4.25 4.5 2.25 5 1.5 4.5 3
And I want to get a row that's the equivalent of
> c(a=5, b=4.25, c=4.5)
a b c
5.0 4.25 4.5
解决方案
x[r,]
where r is the row you're interested in. Try this, for example:
#Add your data
x <- structure(list(A = c(5, 3.5, 3.25, 4.25, 1.5 ),
B = c(4.25, 4, 4, 4.5, 4.5 ),
C = c(4.5, 2.5, 4, 2.25, 3 )
),
.Names = c("A", "B", "C"),
class = "data.frame",
row.names = c(NA, -5L)
)
#The vector your result should match
y<-c(A=5, B=4.25, C=4.5)
#Test that the items in the row match the vector you wanted
x[1,]==y
This page (from this useful site) has good information on indexing like this.
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