与start.process在.NET运行R.脚本 [英] Run R script with start.process in .net
问题描述
我想运行在vb.net中的R脚本,从而节省数据.csv文件。到现在我发现了以下的方法:
暗淡strCmd为String
strCmd =R CMD一批+C:\ test.R
的Process.Start(的CMD.exe,strCmd
显然这应该工作,但在我的情况下,CMD弹出(在我的debug文件夹lokated),并没有任何反应。
另一种方式我想是
的Process.Start(Rgui.exe,C:\ test.R)
错误消息:参数C:\ test.R忽略
这是不工作要么。
我的ř剧本我只是用一个例子
汇()
setwd(C:/)
X - LT; - data.frame(A = I(一个\报价),B =圆周率)
沉(test.csv)
这是怎么对我的作品:
昏暗myprocess随着新工艺
myprocess.StartInfo =新的ProcessStartInfo(C:\ Program Files文件(x86)的\ r \ R-2.6.2 \ BIN \里面运行R.exe,CMD料C:/Users/test/test3.RC:/用户/测试/testout.csv)
myprocess.Start()
第二个方法(第一个应用程序犯规给了我一个很好的CSV输出,所以在这里,这是一个解决办法。):
昏暗的PROC =新工艺
proc.StartInfo.FileName =C:\ Program Files文件(x86)的\ r \ R-2.6.2 \ BIN \ Rscript.exe
proc.StartInfo.WorkingDirectory =C:\ Program Files文件(x86)的\ r \ R-2.6.2 \ BIN
proc.StartInfo.Arguments =C:/Users/Desktop/RtoVB/test4.r
proc.StartInfo.UseShellExecute = TRUE
proc.StartInfo.RedirectStandardOutput = FALSE
proc.Start()
I want to run an r script in vb.net which saves data in a .csv file. Till now i found the following approaches:
dim strCmd as String
strCmd = "R CMD BATCH" + "C:\test.R"
process.start("CMD.exe", strCmd
apparently this should work but in my case the cmd pops up (lokated in my debug folder) and nothing happens.
Another way i tried was
process.start("Rgui.exe", "C:\test.R")
Error Message: Argument "C:\test.R" ignored
this is not working either.
for my r script i just used an example
sink()
setwd("C:/")
x <- data.frame(a = I("a \" quote"), b = pi)
sink(test.csv)
this is how it works for me:
Dim myprocess As New Process
myprocess.StartInfo = New ProcessStartInfo("C:\Program Files (x86)\R\R-2.6.2\bin\R.exe", "CMD BATCH C:/Users/test/test3.R C:/Users/test/testout.csv")
myprocess.Start()
second approach (first app. doesnt give me a good csv output so here this is a workaround):
Dim proc = New Process
proc.StartInfo.FileName = "C:\Program Files (x86)\R\R-2.6.2\bin\Rscript.exe"
proc.StartInfo.WorkingDirectory = "C:\Program Files (x86)\R\R-2.6.2\bin"
proc.StartInfo.Arguments = "C:/Users/Desktop/RtoVB/test4.r"
proc.StartInfo.UseShellExecute = True
proc.StartInfo.RedirectStandardOutput = False
proc.Start()
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