保存前检查重复的XML，如果找到重复，请告诉我 [英] XML checking for duplicates before saving, if duplicate found tell me about it

问题描述

嗨Guys / Gals，



在这里打了一小撮（这对我来说还是很新的，所以宝贝语言）;



我想检查重复项，如果我尝试输入相同的值，则会出现一个消息框告诉我，我想检查APIKEY和VCODE。如果它们匹配我的XML中已有的值，我不希望它再次添加。

 <？  xml     version   =  1.0   < span class =code-summarycomment> encoding   =  utf-8 ？ >  
 <  < span class =code-leadattribute> APISAVE     xmlns：xsi   =  http://www.w3.org/2001/XMLSchema-instance    xmlns：xsd   =  http://www.w3.org/2001/XMLSchema > ;  
 <   ID   >  3e9316bc-6190-4d1d-81e1-9130755ee0ad <   / ID  >  
 <   APIKEY  >  1234 <   / APIKEY  >  
 <   VCODE  >  1234 <   / VCODE  >  
 <   / API保存 >  <？  xml     version   =  1.0    encoding   =  utf-8 ？ >  
 <   APISAVE     xmlns：xsi   =  http://www.w3.org/2001/XMLSchema-instance\"   xmlns：xsd   =  http：//www.w3 .org / 2001 / XMLSchema >  
 <   ID  >  c67ade2a-d568-40d2-a72f-29f896903fd1 <   / ID  >  
 < ;   APIKEY  >  1234567 <   / APIKEY  >  
 < ;   VCODE  >  1234567 <   / VCODE  >  
 < ;   / APISAVE  >  <？  xml     version   =  1.0   编码  =  utf-8  ？ >  
 < ;   APISAVE     xmlns：xsi   =  http://www.w3.org/2001/XMLSchema-instance    xmlns：xsd   =  http://www.w3.org/2001/XMLSchema & gt;  
 <   ID  >  12e777f2-910e-443f-ab6d-b1d2053ae12b <   / ID  >  
 <   APIKEY  < span class =code-keyword>>  1234 <   / APIKEY  >  
 <   VCODE  < span class =code-keyword>>  1234 <   / VCODE  >  
 <   / APISAVE  >  

我的代码看起来像这样



APISAVE.cs：

  public   class  APISAVE 
 {
  static   void  main（ string  [] args）
 {
 XmlDocument xmldoc =  new  XmlDocument（）; 
 xmldoc.Load（  data.XML）; 
 XmlNodeList userNodes = xmldoc.SelectNodes（  data.XML）; 
  foreach （ userNodes中的XmlNode userNode ）; 
 
} 
 
  private   string  id; 
  private   string  APIkey; 
  private   string  VCode; 
 
  public   string  ID 
 {
  get  { return  id; } 
  set  {id = Guid.NewGuid（）。ToString（）; } 
} 
 
  public   string  APIKEY 
 { 
  get  { return  APIkey; } 
  set  {APIkey =  value ; } 
} 
 
  public   string  VCODE 
 { 
  get  { return  VCode; } 
  set  {VCode =  value ; } 
 
} 
 
  public   static   void  SaveData（ object  obj， string 文件名）
 {
 
 XmlSerializer sr =  new  XmlSerializer（obj.GetType（））; 
 TextWriter writer =  new  StreamWriter（文件名， true ）; 
 sr.Serialize（writer，obj）; 
 writer.Close（）;这是我的按钮：
 
 
 
 
  private   void  button1_Click（ object  sender，EventArgs e）
 {
 {
  try  
 {
 
 
 APISAVE info =  new  APISAVE（）; 
 info.APIKEY = txtAPI.Text; 
 info.VCODE = txtVerC.Text; 
 info.ID = info.ID; 
 APISAVE.SaveData（info，  data.XML）; 
 
} 
 
  catch （例外情况）
 
 {
 MessageBox .Show（ex.Message）; 
} 
} 
} 
 
 
 
 
 
我的最终目标是使用数据稍后放在这里。
解决方案
 
如果可以使用序列化，为什么要自己处理XML？请参阅：
 
  https://en.wikipedia.org/wiki/Serialization  [< a href =https://en.wikipedia.org/wiki/Serializationtarget =_ blanktitle =New Window> ^ ]，
 
 http://msdn.microsoft.com/en-us/library/ms733127.aspx  [ ^ ]。
 
 
 
 
 -SA 
 
 
 
Hi Guys/Gals,



struggeling a little here (this is all still really new to me so baby language); 



I want to check for duplicates and if I try and enter in the same value a message box comes up telling me, I want to check APIKEY and VCODE. If they match values already in my XML I don't want it to add again.



<?xml version="1.0" encoding="utf-8"?>
<APISAVE xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ID>3e9316bc-6190-4d1d-81e1-9130755ee0ad</ID>
  <APIKEY>1234</APIKEY>
  <VCODE>1234</VCODE>
</APISAVE><?xml version="1.0" encoding="utf-8"?>
<APISAVE xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ID>c67ade2a-d568-40d2-a72f-29f896903fd1</ID>
  <APIKEY>1234567</APIKEY>
  <VCODE>1234567</VCODE>
</APISAVE><?xml version="1.0" encoding="utf-8"?>
<APISAVE xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
  <ID>12e777f2-910e-443f-ab6d-b1d2053ae12b</ID>
  <APIKEY>1234</APIKEY>
  <VCODE>1234</VCODE>
</APISAVE>




My Code looks like this



APISAVE.cs:



public class APISAVE
    {
        static void main(string[] args)
        {
            XmlDocument xmldoc = new XmlDocument();
            xmldoc.Load("data.XML");
            XmlNodeList userNodes = xmldoc.SelectNodes("data.XML");
            foreach (XmlNode userNode in userNodes) ;

        }

        private string id;
        private string APIkey;
        private string VCode;

        public string ID
        {
             get { return id; }
             set { id = Guid.NewGuid().ToString(); }
        }

        public string APIKEY
        {
            get { return APIkey; }
            set { APIkey = value; }
        }

        public string VCODE
        {
            get { return VCode; }
            set { VCode = value; }

        }

        public static void SaveData(object obj, string Filename)
        {

            XmlSerializer sr = new XmlSerializer(obj.GetType());
            TextWriter writer = new StreamWriter(Filename, true);
            sr.Serialize(writer, obj);
            writer.Close();

        }
    }




Here is my Button:



private void button1_Click(object sender, EventArgs e)
{
    {
        try
        {


            APISAVE info = new APISAVE();
            info.APIKEY = txtAPI.Text;
            info.VCODE = txtVerC.Text;
            info.ID = info.ID;
            APISAVE.SaveData(info, "data.XML");

        }

        catch (Exception ex)

        {
            MessageBox.Show(ex.Message);
        }
    }
}




my end goal is to use the data put in here later on.
解决方案
Why dealing with XML by yourself if you can use serialization instead? Please see:

https://en.wikipedia.org/wiki/Serialization[^],

http://msdn.microsoft.com/en-us/library/ms733127.aspx[^].



—SA


                        
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