代码运行时无法提供字符 [英] can't feed character when code runs

问题描述

我是编程新手。我已经为下面提到的问题写了一个代码

Q.如果

条件：

1，司机已经投保了/>
2）司机未婚，男性，30岁以上

3）司机未婚，女性，25岁以上

问题我面临的是 - 进入年龄后我无法进入婚姻状态，输出屏幕看起来像这样 -

输入年龄：28

输入婚姻状况m / u输入性别m / f（当我在这里给出一个角色，程序结束）

司机没有投保

代码如下。

A.

Hi I am new to programming. I have written a code for a problem mentioned below
Q. A driver is insured if
conditions:
1)Driver is married
2)Driver is unmarried,male,above 30 yrs of age
3)Driver is unmarried,female,above 25 yrs of age
The problem I am facing is- after entering age I am not able to enter marital status, the output screen looks like this-
Enter age: 28
Enter marital status m/u Enter sex m/f ("when i give a character here the program ends")
Driver is not insured
Code is given below.
A.

#include<stdio.h>

 int main()
 {
    int a; //variable a for age

    char ms,sx; //ms for marital status, sx for sex

    printf("Enter age: ");
    scanf("%d",&a);
    printf("Enter marital status m/u ");
    scanf("%c",&ms);
    printf("Enter sex m/f ");
    scanf("%c",&sx);

    if((ms=='m')||(a>30&&ms=='u'&&sx=='m')||(a>25&&ms=='u'&&sx=='f'))
        printf("Driver is insured");
    else
        printf("Driver is not insured");

 return 0;
 }

推荐答案

从 scanf 获取单个字符非常棘手（例如，参见如何在单个字符中执行scanf Cat Stack Overflow [ ^ ]）。



正如那里建议的那样，你可以改成

Getting a single character from scanf is tricky (see, for instance "How to do scanf for single char in C" at Stack Overflow[^]).

As suggested there, you could change from

Quote：

scanf（％c，& ms）;

scanf("%c",&ms);

to

to

scanf(" %c",&ms);

注意％c 之前的空白。







以同样的方式，来自

Note the blank before %c.



And in the same way, from

Quote：

scanf（％ c，& sx）;

scanf("%c",&sx);

to

to

scanf(" %c",&sx);

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