如何在不同方法中输入最小值，最大值和平均值的命令 [英] How to put commands for minimum, maximum and average of numbers in different methods

问题描述

using System;
using System.Linq;

public class Test
{
    public static void Main()
    {
        const int NUMBERS = 1000;
        Random myRandom = new Random();
        int [] a = new int[NUMBERS];

        int i = 0;
        int max = int.MinValue, min = int.MaxValue, sum = 0;


       while (i < NUMBERS)
        {
          a[i] = myRandom.Next(1, 501);
          if (max < a[i]) max = a[i];
          if (min > a[i]) min = a[i];
          sum += a[i];
          ++i;
        }
        double avg = (double)sum / NUMBERS;

        Console.WriteLine("The minimum number is: {0}", min );
        Console.WriteLine("The maximum number is: {0}", max);
        Console.WriteLine("The average of these numbers is: {0}", avg);

        int x = Convert.ToInt32(Console.ReadLine());

       if(a.Contains(x))
       {
        Console.WriteLine("Your number was one of the original 1000!");
       }
       else
       {
        Console.WriteLine("Your number was not one of the original 1000");
       }

  }
}

推荐答案

为什么不简单地使用LINQ Min [ ^ ]和Max [ ^ ]方法。



[加法]



请考虑以下代码

Why not simply use LINQ Min[^] and Max[^] methods.

[Addition]

Consider the following code

int[] myarray = new int[5] { 3, 5, 9, 2, 5 };
System.Diagnostics.Debug.WriteLine(string.Format("Minimum is {0}", myarray.Min()));
System.Diagnostics.Debug.WriteLine(string.Format("Maximum is {0}", myarray.Max()));
System.Diagnostics.Debug.WriteLine(string.Format("And somewhere between is {0}", myarray.Average()));

输出为

The output is

Minimum is 2
Maximum is 9
And somewhere between is 4,8

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