我在使用fetch对象使用数据时无法获取数据 [英] i m unable to fetch data while using data using fetch object
问题描述
if(isset($_POST['editvalue']))
{
$qrys = mysql_query("select * from employee where empid='{$_POST[ide]}'") or die(mysql_error());
$rows = mysql_fetch_object($qrys);
exit();
}
ajax呼叫:
$(body)。delegate('。edit','click',function(){
var IdEdit = $(this).attr('ide');
alert(IdEdit);
$ .ajax({
url:index.php,
键入:POST,
数据:{
editvalue:1,
ide:IdEdit
},
成功:功能(显示)
{
$(#id)。val(show.id);
$(#name)。val(show.name);
$(#mob)。val(show.mob);
$(#gender)。val(show.gender);
}
});
});
ajax calling :
$("body").delegate('.edit','click',function(){
var IdEdit = $(this).attr('ide');
alert(IdEdit);
$.ajax({
url : "index.php",
type: "POST",
data:{
editvalue :1,
ide :IdEdit
},
success: function(show)
{
$("#id").val(show.id);
$("#name").val(show.name);
$("#mob").val(show.mob);
$("#gender").val(show.gender);
}
});
});
< form action =#method =post> ;
< input type =hiddenid =id>
员工姓名 | : | < input type =textid =namename =namevalue =if(isset($ _ GET ['ide'])) { echo $ rows->名称; } ?>/> |
Mobile | : | < input type =textid =mobname =mob> |
性别 | : | < input type =textid =gendername =gender> |
< input type =buttonvalue =save id =save> |
< / form>
<form action="#" method="post">
<input type="hidden" id="id">
Employee Name | : | <input type="text" id="name" name="name" value=" if(isset($_GET['ide'])) { echo $rows->Name; } ?>"/> |
Mobile | : | <input type="text" id="mob" name="mob" > |
Gender | : | <input type="text" id="gender" name="gender" > |
<input type="button" value="save" id="save"> |
</form>
< br $>
<桌边=1>
Emp ID | Emp Name | Emp Mobile | Emp Gender | Action |
---|
获取错误:undifiend对象:行并尝试获取非对象值行121
getting error : undifiend object : rows and trying to get non object values line no 121
推荐答案
_POST [' editvalue']))
{
_POST['editvalue'])) {
qrys = mysql_query( select * from employee where empid ='{
qrys = mysql_query("select * from employee where empid='{
_POST [ide]}')或 die(mysql_error());
_POST[ide]}'") or die(mysql_error());
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