如何检查字符串是否与对象不相等？ [英] How do you check if a string is not equal to an object?

问题描述

我想要使用的代码！=符号。但由于我使用String，我怎么不等于Sign。她是我的代码。所以我希望所有这些声明都不相等，所以它可以打印Tie Game。

  if （数组[ 0 ] ==数组[currentPlayer]&&数组[ 1 ] == 
数组[currentPlayer]&&数组[ 2 ] ==数组[currentPlayer]）
 

以上代码是指一切都相等的时候。但我希望这些陈述不要相等。

例如，

数组[ 0 ] ==数组[currentPlayer]&&数组[ 1 ] ==数组[currentPlayer] 
 
&&数组[ 2 ] ==数组[currentPlayer]不等于数组[ 0 ] ==数组[currentPlayer] 
 
&&数组[ 1 ] ==数组[currentPlayer]&&数组[ 2 ] ==数组[currentPlayer] 

然后打印领带游戏。





请记住我没有使用过Int或Char，我正在使用String。

解决方案

看看这里：比较字符串和字符串部分 [ ^ ]



正如我在评论中提到的，你必须对数据进行操作，而不是对字符串进行操作。 Java是非常强大的编程语言。它可以创建自定义类，例如

  //  < span class =code-comment> definition  
  public   class  Player { 
  public   String 名称; 
  public  Int Score; 
 
  public  Player（ String  n，Int s）{
名字= n; 
得分= s; 
} 
 
  public  toString（）{
  return 名称+  得分为： + Score.toString（）; 
} 
} 
 
  //  实施： 
 ArrayList< player> players =  new  ArrayList< player>（）; 
 players.Add（ new 播放器（  Adam， 50 ））; 
 players.Add（ new 播放器（  Eve， 55 ））; 
 
  //  其他内容......  
播放器播放器1 = players.get（ 0 ）; 
玩家player2 = players.get（ 1 ）; 
  if （player1.equals（player2））{
  //  两个对象在名称和分数上相等 
} 

你们看看差异？



有关比较Java中对象的更多信息，请参阅： Java编程：比较对象 [ ^ ]

您使用等于方法。



< pre lang =java> if （！someVariable.equals（ Bob））
System.out.println（ 不是Bob！ ）;
else
System.out.println（ 是Bob !!）;

查看此链接了解更多详情：

Java - String equals（）方法 [ ^ ]

I ave a code where I want to use != sign. But since I am using String, How do I not equals Sign. Hers is my code. So I want all this statement not to equal to each other so it can print Tie Game.

if (Array[0] == Array[currentPlayer] &&  Array [1] ==
   Array[currentPlayer] && Array [2] == Array[currentPlayer])

The above code is when everything equals to each other. But I want this statements not to equal each other.
For example,

Array[0] == Array [currentPlayer] && Array[1] == Array [currentPlayer] 

&& Array[2]== Array [currentPlayer]  doesnot equal Array[0] == Array [currentPlayer]

&& Array[1] == Array [currentPlayer] && Array[2]== Array[currentPlayer]

then print Tie Game.


Keep in mind that I have not used Int or Char, I am using String.

解决方案

Have a look here: Comparing Strings and Portions of Strings[^]

As i mentioned in comment, you have to operate on data, not on strings. Java is really powerful programming language. It enables to create custom classes, such as

//definition
public class Player{
    public String Name;
    public Int Score;

    public Player(String n, Int s){
        Name = n;
        Score = s;
    }

    public toString() {
        return Name + "'s score is: " + Score.toString();
    }
}

//Implementation:
ArrayList<player> players = new ArrayList<player>();
players.Add(new Player("Adam", 50));
players.Add(new Player("Eve", 55));

//other stuff...
Player player1 = players.get(0);
Player player2 = players.get(1);
if(player1.equals(player2)){
//two objects are equal on Name and Score
}

Do you see the difference?

For further information about comparing objects in Java, please see: Java Programming: Comparing Objects[^]

You use the equals method.

if (!someVariable.equals("Bob"))
    System.out.println("Is not Bob!");
else
    System.out.println("Is Bob!!");

Check out this link for more details:
Java - String equals() Method[^]

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