在trim（）之后获取字符串的最后一个字符不起作用 [英] Getting the last character of a string is not working after trim()

问题描述

如何从字符串中删除空格以获取最后一个字符？

How to remove the white spaces from string, in order to get the last character?

const email = "abc@";
const emailWhiteSpace = "abc@ ";
console.log(email.trim()[email.length - 1]) //==> @
console.log(emailWhiteSpace.trim()[emailWhiteSpace.length - 1]) //==> undefinied

任何想法如何解决这个问题？

Any idea how to solve this issue?

推荐答案

使用正则表达式可能更容易 - 匹配非空格字符，后跟空格字符，后跟行尾（ $ ）：

It might be easier to use a regular expression - match a non-space character, followed by space characters, followed by the end of the line ($):

const lastChar = str => str.match(/(\S)(?=\s*$)/)[1];
console.log(lastChar("abc@"));
console.log(lastChar("abc@ "));

当然，您也可以将修剪过的文字保存在变量：

Of course, you can also save the trimmed text in a variable:

const lastChar = str => {
  const trimmed = str.trim();
  return trimmed[trimmed.length - 1];
};
console.log(lastChar("abc@"));
console.log(lastChar("abc@ "));

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