有一个产品的风味是另一个孩子 [英] Have a product flavor be a child of another

问题描述

我设立了产品的味道在我的应用程序，并遇到了一个问题。我的两个产品的口味非常相似，彼此只相差几个资源，我们姑且称之为FlavorA和FlavorB。我想设置它，以便FlavorA是FlavorB的父母，这样FlavorB可以只覆盖FlavorA的一些资源，然后FlavorA覆盖了一堆资源从主。有没有办法建立一个层次的味道像这样？现在我需要复制大量两者之间的资源，以便为它工作，我想，以消除重复。

编辑：OK。我有一对夫妇的答案为止（包括删除）这是不相关的，我的问题所以让我澄清一下。这不都与Java的面向对象，我已经知道了相当不错的。 ：）

我遇到的问题是，我有一个免费/付费版本我的应用程序，然后几个白色的标签，只有包括主题更改。付费版只能从免费版本（除了code的变化）改变了一些资产。这是我的 productFlavors 是这样的：

  productFlavors {
        whiteLabelA {
            的applicationIDcom.whiteLabelA.android
        }

        whiteLabelB {
            的applicationIDcom.whiteLabelB.android
        }

        mainFree {
            的applicationIDcom.mainFree.android
        }

        mainPaid {
            的applicationIDcom.mainFree.android.paid
        }
    }
 

我想 mainPaid 来替代 mainFree ，因为它只是改变了一些资源。我想这样来做，而不是免费/付费版本的类型，因为白色的标签，没有付费版本，它会更容易有一样的味道层次：

  mainPaid延伸mainFree {
    的applicationIDcom.mainFree.android.paid
}
 

解决方案

我想你不会是能够做到这一点，在机器人对象直接，但你可以使用配置的函数，在一番风味设置公共属性。在安卓之后将这个目标：

 无效configureWhiteLabelFlavor（味）{
    flavor.useJack =真
}

configureWhiteLabelFlavor（android.productFlavors.whiteLabelA）
 

如果需要，您可以通过呼叫其他功能，从这个功能实现深继承。

I'm setting up the product flavors in my app and have run into one problem. Two of my product flavors are very similar to each other and only differ by a few resources, let's call them FlavorA and FlavorB. I would like to set it up so that FlavorA is the parent of FlavorB, that way FlavorB can just override a few resources of FlavorA, and then FlavorA overrides a bunch of resources from main. Is there a way to set up a flavor hierarchy such as this? Right now I need to duplicate lots of resources between the two in order for it to work and I would like to eliminate that duplication.

edit: OK. I've had a couple answers so far (both deleted) that were not related to my question so let me clarify. This does not have to do with Java OOP, I already know that quite well. :)

The issue I'm having is that I have a free/paid version of my app, and then several white labels that only include theme changes. The paid version only changes a few assets from the free version (apart from code changes). This is what my productFlavors look like:

productFlavors {
        whiteLabelA {
            applicationId "com.whiteLabelA.android"
        }

        whiteLabelB {
            applicationId "com.whiteLabelB.android"
        }

        mainFree {
            applicationId "com.mainFree.android"
        }

        mainPaid {
            applicationId "com.mainFree.android.paid"
        }
    }

I would like mainPaid to override mainFree since it only changes a few resources. I would like to do it this way rather than a free/paid build type because the white labels don't have paid versions, and it would be easier to have a flavor hierarchy like:

mainPaid extends mainFree {
    applicationId "com.mainFree.android.paid"
}

解决方案

I think you won't be able to do this in the android object directly, but you can use a configuration function to set common properties on a flavor. Put this after the android object:

void configureWhiteLabelFlavor(flavor) {
    flavor.useJack = true
}

configureWhiteLabelFlavor(android.productFlavors.whiteLabelA)

If needed, you can implement deep inheritance by calling other functions from this function.

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