帮助：警告：mysql_fetch_array（）期望参数1是资源，在第20行（和第21行）的C：\ xampp \\\\\\\\\\\\\\\\\\\\\\\\ [英] HELP: Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\connect.php on line 20 (and line 21)

问题描述

有人可以告诉我为什么我无法通过这些警告并访问我的网页。谢谢



警告：mysql_fetch_array（）要求参数1为资源，在第20行的C：\ xampp \\\\\\\\\\\\\\\\\\\\\\\\\ br $> b $ b

警告：mysql_fetch_array（）期望参数1为资源，第21行的C：\ xampp \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

Can someone please tell me why i cant get past these warnings and access my webpage. Thank you

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\connect.php on line 20

Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in C:\xampp\htdocs\connect.php on line 21

$inputuser = $_POST['user'];
$inputpass = $_POST['pass'];
$user = "root";
$password = "";
$database = "gis";

$connect = mysql_connect("localhost",$user,$password);

@mysql_select_db($database) or ("Database not found");

$query = "SELECT * FROM 'users' WHERE 'user' = '$inputuser'";
$querypass = "SELECT * FROM 'users' WHERE 'password' = '$inputpass'";

$result = mysql_query($query);
$resultpass = mysql_query($querypass);

$row = mysql_fetch_array($result);
$rowpass = mysql_fetch_array($resultpass);

$serveruser = $row["user"];
$serverpass = $row["password"];

if($serveruser&&$serverpass){
	if(!$result){
		die("Username or password is invalid");
	}

	echo "Database output";
	mysql_close();

	echo $inputpass;
	echo $serverpass;

if($inputpass == $serverpass) {

	header('Location: Home.php');

}else{

	echo "Sorry that is not the correct information";
}
}

推荐答案

inputuser =

inputuser =

_POST [' user'];

_POST['user'];

inputpass =

inputpass =

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