c中作为函数参数的字符指针 [英] pointer of character in as function parameter in c

问题描述

我有接受来自用户的字符串的函数

i have function that accept string from user

int findAscii(char* n)
 
   {
 
    //function body here
}

和

and

int findAscii(char *n)
 
{
 
//function body here
}

问题是两个函数中的n值是否相同？ （函数是等价的？）

the question is does n have the same value in both functions ? (functions are equivalent ?)

推荐答案

你的参数类型是char *，名称是n。你放在哪里*，（char *）n或（char *）n是等价的无关紧要

the type of your argument is char* and the name is n. It does not matter where you put *, (char*)n or (char *)n is equivalent

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