C ++函数指针作为参数 [英] C++ function pointer as parameter
本文介绍了C ++函数指针作为参数的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我尝试调用一个作为函数指针传递而没有任何参数的函数, > void * disconnectFunc;
void D :: setDisconnectFunc(void(* func)){
disconnectFunc = func;
}
void D :: disconnected(){
* disconnectFunc;
connected = false;
}
解决方案
正确的方法是:
typedef void(* callback_function)(void); // type for intiseness
callback_function disconnectFunc; //变量存储函数指针类型
void D :: setDisconnectFunc(callback_function pFunc)
{
disconnectFunc = pFunc; // store
}
void D :: disconnected()
{
disconnectFunc(); // call
connected = false;
}
I try to call a function which passed as function pointer with no argument, but I can't make it work.
void *disconnectFunc;
void D::setDisconnectFunc(void (*func)){
disconnectFunc = func;
}
void D::disconnected(){
*disconnectFunc;
connected = false;
}
解决方案
The correct way to do this is:
typedef void (*callback_function)(void); // type for conciseness
callback_function disconnectFunc; // variable to store function pointer type
void D::setDisconnectFunc(callback_function pFunc)
{
disconnectFunc = pFunc; // store
}
void D::disconnected()
{
disconnectFunc(); // call
connected = false;
}
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