如果第一个查询中的结果存在于第二个查询中,如何删除结果? [英] How do I remove results from the first query, if they exist in a second query?
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问题描述
如果第一个查询中的结果存在于第二个查询中,如何删除结果?
我查看过以前的stackoverflow线程但仍无法使其工作。
我的 MySQL
目前的查询如下:
How do I remove results from the first query, if they exist in a second query?
I've looked over previous stackoverflow threads and still can't get it to work.
My MySQL
queries so far are below:
SELECT roomL.CityCode, roomL.TableCode
FROM (SELECT roomL.CityCode, roomL.TableCode
FROM roomL
WHERE roomL.StatusEnum = 1
AND roomL.TableCode NOT IN (select stock.TableCode from stock)
AND roomL.TimeSeen BETWEEN 10/10/2014 AND Now())
WHERE NOT EXISTS (SELECT roomL.CityCode , roomL.TableCode
FROM roomL
WHERE roomL.StatusEnum = 1
AND roomL.TableCode NOT IN (select stock.TableCode from stock)
AND roomL.TimeSeen BETWEEN DATE_ADD( 17/10/2014 ,INTERVAL 1 DAY) AND Now())
目前我收到错误消息:
SQL错误(1248):每个派生表必须有自己的别名
推荐答案
试试这个希望它会帮到你
try this hope it will help you
SELECT roomL.CityCode, roomL.TableCode
FROM (SELECT roomL.CityCode, roomL.TableCode
FROM roomL
WHERE roomL.StatusEnum = 1
AND roomL.TableCode NOT IN (select stock.TableCode from stock)
AND roomL.TimeSeen BETWEEN 10/10/2014 AND Now()) as x
WHERE roomL.CityCode+'#'+roomL.TableCode Not in
(SELECT roomL.CityCode+'#'+roomL.TableCode
FROM roomL
WHERE roomL.StatusEnum = 1
AND roomL.TableCode NOT IN (select stock.TableCode from stock)
AND roomL.TimeSeen BETWEEN DATE_ADD( 17/10/2014 ,INTERVAL 1 DAY) AND Now())
SELECT RL.CityCode, RL.TableCode
FROM (SELECT roomL.CityCode, roomL.TableCode
FROM roomL
WHERE roomL.StatusEnum = 1
AND roomL.TableCode NOT IN (select stock.TableCode from stock)
AND roomL.TimeSeen BETWEEN 10/10/2014 AND Now()) RL
WHERE RL.CityCode Not in
(SELECT roomL.CityCode
FROM roomL
WHERE roomL.StatusEnum = 1
AND roomL.TableCode NOT IN (select stock.TableCode from stock)
AND roomL.TimeSeen BETWEEN DATE_ADD( 17/10/2014 ,INTERVAL 1 DAY) AND Now())
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