如何根据C＃中的某些条件从XML文件中读取数据？ [英] How to Read data from a XML file based on some condition in C#?

问题描述

如何根据C＃中的某些条件从xml文件中读取数据？



请建议我.....

How to read data from a xml file based on some condition in C#?

Please Suggest Me.....

推荐答案

嗨


要从xml文件中读取数据，我首先将xml序列化为强类型对象。



查看此



从-XML到强类型在C





基本上使用类可以将xml文件序列化为对象，然后在c＃中正常使用。



这有用吗？

Hi
To read data from xml file I would first serialize the xml to a strongly typed object.

Check this

From-XML-to-Strong-Types-in-C


Basically using a class you can serialize the xml file to an object and then use this as normal in your c#.

Does this help?

您没有根据您想要读取数据的条件提及

使用linq您可以这样做。



检查这些链接可能会对你有所帮助。





http://stackoverflow.com/questions/1549908 2 / linq-to-xml-fetching-value-based-on-condition [ ^ ]



http://www.c-sharpcorner.com/UploadFile/54db21/ select-data-from-xml-with-where-clause-using-linq-to-xml / [ ^ ]

You didn't mention based on what condition you want to read data but
Using linq you can do this.

Check these link it may help you.


http://stackoverflow.com/questions/15499082/linq-to-xml-fetching-value-based-on-condition[^]

http://www.c-sharpcorner.com/UploadFile/54db21/select-data-from-xml-with-where-clause-using-linq-to-xml/[^]

你也可以在LINQ中使用类XDocument，XElement，XAttribute等。

这种方法不是强类型的，但你必须手动阅读结构。



System.Xml.Linq命名空间 [ ^ ]



小例子：

You can also use the classes XDocument, XElement, XAttribute etc. in LINQ.
This approach is not strongly typed, but you have to read the structure manually.

System.Xml.Linq Namespace[^]

Small example:

XDocument xd = new XDocument();
xd.Load(@"SomeFile.xml");

// Get the first element with the name 'SomeNode'
XElement xe = xd.Element("SomeNode");
etc.

如果您只想读取数据，这是XSD的一个很好的替代方案。

This is a good alternative to XSD if you only want to read the data.

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