如何压缩xml和下载 [英] how zip the xml and download

问题描述

我有一个数据集。我希望将其保存为xml并压缩以供用户下载。

我使用下面的代码。

xml文件保存但保存对话框没有出现。如何将其压缩并向用户显示保存对话框

I have a dataset .I want save it as xml and zip it for user download it .
I use code below.
the xml file saves but the save dialog doesn't appear .how can I zip it and show save dialog to user

 datasetKetab dsk = new datasetKetab();
Ketab ketab = (from k in jle.Ketabs where k.KetabID == ketabid select k).Single();
                    dsk.Ketab.AddKetabRow(ketab.Nam, ketab.TedadeSafhe.Value, ketab.TedadeSoal.Value, ketab.Aks);
dsk.WriteXml(@"C:\Users\moslem\Desktop\a.xml");

确定它有效。 linested lonic我使用了system.io.compression.zip文件

但是我收到一个错误：该进程无法访问文件，因为zip文件名文件正由另一个进程使用

xml和zip文件在该文件夹中创建，但文件不会下载。为什么？

ok it works. inested lonic I used system.io.compression.zipfile
but I get an error:"the process cannot access file because "zip file name" the file is using by another process"
xml and zip file is created in that folder but file will not download . why?

string directoryname=MapPath("path...");
                    string xmlfile = MapPath("path..." + ketab.Nam + ".xml");
                    dsk.WriteXml(xmlfile);
                    Response.ClearContent();
                    Response.ClearHeaders();
                                       Response.ContentType = "application/zip";
                    Response.AppendHeader("content-disposition", "attachment; filename=Report.zip");
                    string zipfile=MapPath("path..." + ketab.Nam+".zip");

                    ZipFile.CreateFromDirectory(directoryname, zipfile);//error is in this line
                    //File.Delete(xmlfile);
                    Response.WriteFile(zipfile);

推荐答案

dt.TableName =声明;

Response.ClearContent（）;

Response.ClearHeaders（）;

Response.ContentType =application / zip;

Response.AppendHeader（content-disposi

dt.TableName = "Declaration";
Response.ClearContent();
Response.ClearHeaders();
Response.ContentType = "application/zip";
Response.AppendHeader("content-disposi

tion，attachment; filename = Report.zip）;



使用（Ionic.Zip.ZipFile zipFile = new Ionic.Zip.ZipFile（））

{

zipFile.AddEntry（Report.xml，（name，stream）=> dt.WriteXml（stream））;

zipFile.Save（Response.OutputStream）;

}

tion", "attachment; filename=Report.zip");

using(Ionic.Zip.ZipFile zipFile = new Ionic.Zip.ZipFile())
{
zipFile.AddEntry("Report.xml", (name,stream) => dt.WriteXml(stream) );
zipFile.Save(Response.OutputStream);
}

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