Android的阻力观点平稳 [英] android drag view smooth

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本文介绍了Android的阻力观点平稳的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

我要拖动屏幕上的一些看法。我从触摸听者的ACTION_MOVE改变左侧和顶部的布局参数从动态事件改变自己的立场。有没有一种方法,以拖的项目更加顺畅?因为那朵样的拖的不顺利在所有...这里是code

 公共布尔onTouch(查看视图,MotionEvent motionEvent){
    开关(motionEvent.getAction()){
        案例MotionEvent.ACTION_DOWN:
            DX =(int)的motionEvent.getX();
            DY =(INT)motionEvent.getY();
            打破;

        案例MotionEvent.ACTION_MOVE:
            INT X =(int)的motionEvent.getX();
            INT Y =(INT)motionEvent.getY();
            RelativeLayout.LayoutParams LP =(RelativeLayout.LayoutParams)view.getLayoutParams();
            INT左= lp.leftMargin +(X  -  DX);
            INT顶部= lp.topMargin +(Y  -  DY);
            lp.leftMargin =左;
            lp.topMargin =顶部;
            view.setLayoutParams(LP);
            打破;
    }
    返回true;
}
 

解决方案

而不是和的getY的getX尝试使用motionEvent.getRawX()和motionEvent.getRawY()

I have to drag some views on screen. I am modifying their position by changing left and top of their layout parameters from motion event on ACTION_MOVE from touch listener. Is there a way to "drag" items more smooth? Because tis kind of "dragging" is no smooth at all... Here is the code

public boolean onTouch(View view, MotionEvent motionEvent) {
    switch (motionEvent.getAction()) {
        case MotionEvent.ACTION_DOWN:
            dx = (int) motionEvent.getX();
            dy = (int) motionEvent.getY();
            break;

        case MotionEvent.ACTION_MOVE:
            int x = (int) motionEvent.getX();
            int y = (int) motionEvent.getY();
            RelativeLayout.LayoutParams lp = (RelativeLayout.LayoutParams) view.getLayoutParams();
            int left = lp.leftMargin + (x - dx);
            int top = lp.topMargin + (y - dy);
            lp.leftMargin = left;
            lp.topMargin = top;
            view.setLayoutParams(lp);
            break;
    }
    return true;
}

解决方案

Try to use motionEvent.getRawX() and motionEvent.getRawY() instead of getY and getX

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