如何序列化类列表 [英] How to serialize list of class

问题描述

  public   class  slab 
 {
  public   int  lowerlimit { get ;  set ; } 
  public   int  upperlimit { get ;  set ; } 
  public   int 百分比{ get ;  set ; } 
 
} 
 
  class 计划
 {
  static   void  Main（ string  [] args）
 {
 List< slab> slabs =  new  List< slab>（）; 
 slab s =  new  slab（）; 
 s.lowerlimit =  0 ; 
 s.upperlimit =  200000 ; 
 s.percentage =  0 ; 
 
 slabs.Add（s）; 
 
 s =  new  slab（）; 
 s.lowerlimit =  0 ; 
 s.upperlimit =  200000 ; 
 s.percentage =  0 ; 
 
 slabs.Add（s）; 
 
 XmlSerializer serializer =  new  XmlSerializer（ typeof （slab）， new  XmlRootAttribute（  slabs））; 
 StringWriter writer =  new  StringWriter（）; 
 serializer.Serialize（writer，slabs）; 
} 
} < /   slab  >  < /   slab   >  

解决方案

请看这里： XML序列化和反序列化：第1部分 [ ^ ]

使用List的对象

 XmlSerializer serializer =  new  XmlSerializer（< big>   typeof （slabs） < /   big  > ， new  Xm lRootAttribute（  slabs））; 

而不是

 XmlSerializer serializer =  new  XmlSerializer（ typeof （slab）， new  XmlRootAttribute（ 板坯））; 

public class slab
    {
        public int lowerlimit { get; set; }
        public int upperlimit { get; set; }
        public int percentage { get; set; }

    }
   
    class Program
    {
        static void Main(string[] args)
        {
            List<slab> slabs = new List<slab>();
            slab s = new slab();
            s.lowerlimit = 0;
            s.upperlimit = 200000;
            s.percentage = 0;

            slabs.Add(s);

            s = new slab();
            s.lowerlimit = 0;
            s.upperlimit = 200000;
            s.percentage = 0;

            slabs.Add(s);

            XmlSerializer serializer = new XmlSerializer(typeof(slab), new XmlRootAttribute("slabs"));
            StringWriter writer = new StringWriter();
            serializer.Serialize(writer, slabs);
        }
    }</slab></slab>

解决方案

See here: XML Serialization and Deserialization: Part-1[^]

Use object of List

XmlSerializer serializer = new XmlSerializer(<big>typeof(slabs)</big>, new XmlRootAttribute("slabs"));

instead of

XmlSerializer serializer = new XmlSerializer(typeof(slab), new XmlRootAttribute("slabs"));

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