Android的 - 如何扫描接入点，并选择最强的信号？ [英] Android - How to scan Access Points and select strongest signal?

问题描述

我目前正在写一个类在Android中，将扫描接入点，计算出哪个接入点具有最佳的信号，然后连接到接入点。

I am currently trying to write a class in Android that will Scan for access points, calculate which access point has the best signal and then connect to that access point.

因此​​，应用程序将能够扫描的移动和连接到新的接入点在旅途中。

So the application will be able to scan on the move and attach to new access points on the go.

我有最好的信号工作的扫描和计算。

I have the scanning and calculation of the best signal working.

但是，当涉及到连接到最佳接入点我有麻烦了。

But when it comes to attaching to the best access point I am having trouble.

看来，enableNetwork（网络标识符号，othersTrueFalse）是用于连接到接入点的唯一方法，但是这会导致问题，因为从我的扫描结果，我无法获得与信号最强的无线接入点的ID。

It appears that enableNetwork(netid, othersTrueFalse) is the only method for attaching to an Access point but this causes problems as from my Scan Results I am not able to get the id of the access point with the strongest signal.

这是我的code：

public void doWifiScan(){

  scanTask = new TimerTask() {
  public void run() {
      handler.post(new Runnable() {
          public void run() {
               sResults = wifiManager.scan(getBaseContext()); 
               if(sResults!=null)
               Log.d("TIMER", "sResults count" + sResults.size());
               ScanResult scan = wifiManager.calculateBestAP(sResults);
               wifiManager.addNewAccessPoint(scan);
           }
       });
    }};

    t.schedule(scanTask, 3000, 30000); 
}

---

public ScanResult calculateBestAP(List<ScanResult> sResults){

     ScanResult bestSignal = null;
        for (ScanResult result : sResults) {
          if (bestSignal == null
              || WifiManager.compareSignalLevel(bestSignal.level, result.level) < 0)
            bestSignal = result;
        }

        String message = String.format("%s networks found. %s is the strongest. %s is the bsid",
                sResults.size(), bestSignal.SSID, bestSignal.BSSID);

        Log.d("sResult", message);
        return bestSignal;
}

---

public void addNewAccessPoint(ScanResult scanResult){

    WifiConfiguration wc = new WifiConfiguration();
    wc.SSID = '\"' + scanResult.SSID + '\"';
    //wc.preSharedKey  = "\"password\"";
    wc.hiddenSSID = true;
    wc.status = WifiConfiguration.Status.ENABLED;        
    wc.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.TKIP);
    wc.allowedGroupCiphers.set(WifiConfiguration.GroupCipher.CCMP);
    wc.allowedKeyManagement.set(WifiConfiguration.KeyMgmt.WPA_PSK);
    wc.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.TKIP);
    wc.allowedPairwiseCiphers.set(WifiConfiguration.PairwiseCipher.CCMP);
    wc.allowedProtocols.set(WifiConfiguration.Protocol.RSN);
    int res = mainWifi.addNetwork(wc);
    Log.d("WifiPreference", "add Network returned " + res );
    boolean b = mainWifi.enableNetwork(res, false);        
    Log.d("WifiPreference", "enableNetwork returned " + b );

}

---

当我尝试使用addNewAccessPoint（ScanResult scanResult），它只是增加了一个AP到列表中具有相同的名称作为一个具有最佳信号的设置应用程序，所以我结束了重复的负载，而不是实际连接到它们。

---

When I try to use addNewAccessPoint(ScanResult scanResult) it just adds another AP to the list in the settings application with the same name as the one with the best signal, so I end up with loads of duplicates and not actually attaching to them.

任何人都可以点我的一个更好的解决方案的方向？

Can anyone point me in the direction of a better solution?

推荐答案

只需更改

boolean b = mainWifi.enableNetwork(res, false);

到

boolean b = mainWifi.enableNetwork(res, true); 

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