如何在类中为每个元素添加属性 [英] How to add an attribute in class for each element

问题描述

我有一个如下所示的课程。

 [DataContract] 
 公开 类申请人
 {
 私有  string  titleField; 
  private   string  firstNamesField; 
 
 [DataMember（订单=  1 ）] 
  public  < span class =code-keyword> string 标题
 {
 获取 
 {
  return   this  .titleField; 
} 
  set  
 {
  this  .titleField = 值; 
} 
} 
 [DataMember（订单=  2 ）] 
 公开 字符串 FirstNames 
 {
  get  
 { 
  return   this  .firstNamesField; 
} 
  set  
 {
  this  .firstNamesField = 值; 
} 
} 
} 

我正在将这个类对象转换为XML。 />

  var  app =  new 申请人（）; 
  var  dcs =  new  DataContractSerializer（app.GetType（））; 
  var  ms =  new  MemoryStream（）; 
 dcs.WriteObject（ms，app）; 
  string  xml = Encoding.UTF8.GetString（ms.GetBuffer（）， 0 ，（  int ）ms.Position）; 
  var  doc = XElement.Parse（xml）; 

doc的值看起来如下所示。

 <  申请人    xmlns：i  < span class =code-keyword> =  http://www.w3.org/2001/XMLSchema-instance    xmlns   =  http://schemas.datacontract.org/2004/07/testApp\">  
  <  申请人 >  
 <  标题 > 先生<   / Title  >  
 <   FirstNames  > 申请人<   / FirstNames  >  
 <   /申请人 >  
 <   /申请人 >  

现在，如何在xml中为每个元素添加属性。我想要一个如下所示的XML。

 <  申请人    xmlns：i   =  http://www.w3.org/2001/XMLSchema-instance    xmlns   =  http：// schemas。 datacontract.org/2004/07/testApp\">  
 <  申请人 >  
 <  标题    IsEnabled   =  True > 先生<   / Title  >  
 <   FirstNames     IsEnabled   =  True > 申请人<   / FirstNames  >  
 <   /申请人 >  
 <   /申请人 >  

必须为每个元素添加IsEnabled属性。但我不想解析XML并为每个元素创建属性。是否可以在类中添加属性并将它们作为每个元素的属性？

解决方案

下面的文章解释了类似的问题并提供了解决方案。请检查



DataContract XML序列化和XML属性 [ ^ ]

I have a class which looks like below.

[DataContract]
   public class Applicant
   {
       private string titleField;
       private string firstNamesField;

       [DataMember(Order = 1)]
       public string Title
       {
           get
           {
               return this.titleField;
           }
           set
           {
               this.titleField = value;
           }
       }
       [DataMember(Order = 2)]
       public string FirstNames
       {
           get
           {
               return this.firstNamesField;
           }
           set
           {
               this.firstNamesField = value;
           }
       }
   }

I'm converting this class object into XML.

var app = new Applicant();
var dcs = new DataContractSerializer(app.GetType());
           var ms = new MemoryStream();
           dcs.WriteObject(ms, app);
           string xml = Encoding.UTF8.GetString(ms.GetBuffer(), 0, (int)ms.Position);
           var doc = XElement.Parse(xml);

the value of "doc" will look something like below.

<Applicant xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/testApp">
		<Applicant>
			<Title>Mr</Title>
			<FirstNames>Applicant</FirstNames> 
		</Applicant>
	</Applicant>

Now , how to add an attribute to a each element in xml. I want an XML like below.

<Applicant xmlns:i="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://schemas.datacontract.org/2004/07/testApp">
		<Applicant>
			<Title IsEnabled="True">Mr</Title>
			<FirstNames IsEnabled="True">Applicant</FirstNames>
		</Applicant>
	</Applicant>

The "IsEnabled" attribute has to come for each element. But i don't want to parse XML and create attribute for each element. Is it possible to add a property in the class and make them as a attribute for each element ?

解决方案

Below article explains similar problem and provide a solution. Please check

DataContract XML serialization and XML attributes[^]

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