如何设置顺序搜索 [英] How do I set up a sequential search

问题描述

这是我到目前为止所做的，但我不知道如何设置数组编号的顺序搜索。

公共类赋值实现ActionListener {
 
私有JPanel面板; 
私人JLabel标签，label2; 
 private JTextField text，text2; 
私人JButton按钮，清晰; 
 private String [] numbers = {5658845,4520125,7895122,8777541,8451277,1302850,8080152,4562555,5552012,5050552,7825877,1250255,1005231,6545231,3852085,7576651,7881200,4581002}; 
 
 public Assignment（）{
 JFrame gui = new JFrame（）; 
 gui.setDefaultCloseOperation（JFrame.EXIT_ON_CLOSE）; 
 gui.setTitle（大学费用）; 
 gui.setSize（325,150）; 
 panel = new JPanel（new GridLayout（3,2））; 
 gui.add（小组）; 
 gui.setVisible（true）; 
 label = new JLabel（收费卡号码）; 
 label2 =新JLabel（结果）; 
 text = new JTextField（，10）; 
 text2 = new JTextField（，10）; 
 text2.setEditable（false）; 
 button = new JButton（Enter）; 
 clear = new JButton（Clear）; 
 
 panel.add（label）; 
 panel.add（text）; 
 panel.add（label2）; 
 panel.add（text2）; 
 panel.add（clear）; 
 clear.addActionListener（this）; 
 panel.add（按钮）; 
 button.addActionListener（this）; 
 
} 
 
 
 
 public static void main（String [] args）{
 new Assignment（）; 
} 
 
 @Override 
 public void actionPerformed（ActionEvent e）{
 String action = e.getActionCommand（）; 
 if（action.equals（Clear））{
 text.setText（）; 
 text2.setText（）; 
} 
 else if（action.equals（Enter））{
 
 
} 
 
} 
} 

解决方案

小心使用该名称分配。这是java编程中常见的一个词，可能会被采用。



顺序搜索说明 [ ^ ]

This is what I have so far, but I don't know how to set up a sequential search for the array numbers.

  public class Assignment implements ActionListener{

        private JPanel panel;
        private JLabel label, label2;
        private JTextField text, text2;
        private JButton button, clear;
        private String[] numbers = { "5658845, 4520125, 7895122, 8777541, 8451277, 1302850, 8080152, 4562555, 5552012, 5050552, 7825877, 1250255, 1005231, 6545231, 3852085, 7576651, 7881200, 4581002" };
    
    public Assignment(){
        JFrame gui = new JFrame();
        gui.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
        gui.setTitle("College Expenses");
        gui.setSize(325, 150);
        panel = new JPanel(new GridLayout(3, 2));
        gui.add(panel);
        gui.setVisible(true);
        label = new JLabel("Charge Card Number");
        label2 = new JLabel("Results");
        text = new JTextField("" , 10);
        text2 = new JTextField("" , 10);
        text2.setEditable(false);
        button = new JButton("Enter");
        clear = new JButton("Clear");
        
        panel.add(label);
        panel.add(text);
        panel.add(label2);
        panel.add(text2);
        panel.add(clear);
        clear.addActionListener(this);
        panel.add(button);
        button.addActionListener(this);
        
        }


           
    public static void main(String[] args) {
        new Assignment();
    }

    @Override
    public void actionPerformed(ActionEvent e) {
        String action = e.getActionCommand();
        if (action.equals("Clear")) {
	            text.setText("");
                    text2.setText("");
	        }
        else if (action.equals("Enter")) {
            
            
        }
            
    }
}

解决方案

Carefull with that name "Assignment". That a common word in java programming and might be taken.

Sequencial search explained[^]

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