错误：“total”的参数1的不兼容类型 [英] error: incompatible type for argument 1 of `total'

问题描述

#include <stdio.h>
float total(float, int);

typedef struct BOOK
{
	int serial;
	char title[30];
	char author[30];
	float price[30];
	int quantity;
}BOOK;

int main()
{
	BOOK a[2];
	int x;
	float sum;
	for(x=0;x<2;x++)
	{
           printf("Please Enter Your Book Serial Number :\n");
           scanf("%d", &a[x].serial);
           printf("Please Enter Your Book Title :\n");
   	   scanf("%s", &a[x].title);
           printf("Please Enter Your Book Author :\n");
   	   scanf("%s", &a[x].author);
           printf("Please Enter Your Book Price :\n");
           scanf("%f", &a[x].price);
           printf("Please Enter Book Quantity :\n");
           scanf("%d", &a[x].quantity);
           sum = total(a[x].price, a[x].quantity);
	}
	
    printf("Your Total Is : %.2f\n",sum);
    return 0;
}

float total(float z,int y)
{
	return z*y;
}

推荐答案

总计的第一个参数的类型c $ c>函数是 float ，而 BOOK :: price 的类型是 float * 。

The type of the first parameter of the total function is float, while the type of BOOK::price is float*.

我认为您错误地将价格定义为数组。



更改

I think you mistakenly defined price as an array.

Change

引用：

浮动价格[30 ];

float price[30];

到

to

float price;

这篇关于错误：“total”的参数1的不兼容类型的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！