类型为“节点*"的参数与"BinarySearchTree *"类型的参数不兼容； [英] argument of type "Node *" is incompatible with parameter of type "BinarySearchTree *"

问题描述

 how can i handle this error
argument of type "Node<int> *" is incompatible with parameter of type "BinarySearchTree<int> *"

推荐答案

您没有给我们很多代码来工作-仅一个线-但我认为您已经将自己描绘在一个角落.

我认为是binTree被声明为BST *，而root被删除为Node *-您在注释中暗示了尽可能多的内容，因此您不能为binTree分配root值，因为节点不是BST.


如果要设计二叉树，则通常将诸如Root，Next和Previous之类的节点声明为BST *，而不是将其声明为单独的类-否则到达那里时，您不能将它们视为BST.

我无法提供具体的代码来修复它-我无法读取您的HDD或看到您的屏幕-但请查看您如何定义事物，看看是否可以发现逻辑问题！ :laugh:

You don''t give us a lot of code to work with - just the one line - but I think you have painted yourself into a corner.

What I think is that binTree is declared as BST*, and root is delcared as Node* - you imply as much in your comments, so you can''t assign a root value to binTree because a Node is not a BST.


If you are designing a binary tree, then normally the nodes such as Root, Next, and Previous are declared as BST* not as separate a separate class - otherwise you can''t treat them as BST''s when you get there.

I can''t give you concrete code to fix it - I can''t read your HDD or see your screen - but look at how you have defined things, and see if you can spot the logical problem! :laugh:

嘿，我自己找到了解决方案，实际上我将Node * root声明为私有成员，这就是为什么我无法在其他类中访问它的原因.

hey i found its solution by myself actually i declared Node* root as private member that''s why i can''t access it in other class.

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