根据组成员身份过滤文档库视图 [英] filtering document library view based on group membership

问题描述

我尝试在sharepoint 2010中创建过滤文档库视图，该视图基于没有列用户/组选择器的组成员身份。我使用了CAML查询

< Query> 
< Where> 
< Or> 
< Membership Type =" CurrentUserGroups"> 
< FieldRef Name =" Editor" /> 
 
< / Membership> 
< Eq> 
< FieldRef Name =" Editor" /> 
< Value Type =" Integer"> 
< UserID Type =" Integer" /> 
< / Value> 
< / Eq> 
< /或> 
< / Where> 
< /查询> 

但我没有收到我想要的东西。我的用户只收到他/她被修改的文件。我需要来自同一组的用户看到文件。

解决方案

<会员资格> element允许应用过滤器来返回字段包含当前用户所属的
组的项目。在您的CAML查询中，使用您通过（编辑）字段进行修改来过滤，此字段仅按设计存储用户。

作为变通方法，您可以创建新的人员或组字段"组"，并使用此字段筛选列表视图。 CAML查询如下。

< Query> 
< Where> 
< Or> 
< Membership Type =" CurrentUserGroups"> 
< FieldRef Name =" Group" /> 
< /会员资格> 
< Eq> 
< FieldRef Name =" Group" /> 
< Value Type =" Integer"> 
< UserID /> 
< / Value> 
< / Eq> 
< /或> 
< / Where> 
< /查询> 

最好的问候，

Dennis

I tryed create filtered document library view in sharepoint 2010, based on group membership without column user/group picker. I used CAML query

<Query>
 <Where>
    <Or>
	<Membership Type="CurrentUserGroups">
		<FieldRef Name="Editor"/>
							 
       </Membership>
	<Eq>
	  <FieldRef Name="Editor"/>
 	    <Value Type="Integer">
		<UserID Type="Integer"/>
	    </Value>
	</Eq>
     </Or>
  </Where>
</Query>

but i don't receive what i want. my user receive just files that he/she is modified. i need that users from same group see files.

解决方案

Hi,

The <Membership> element allows apply a filter to return items where the field contains a group of which the current user is a member. In your CAML Query, use you modified by(Editor) field to filter, and this field only store the user by design.

As a workaround, you can create a new Person or Group field "Group", and filter the list view using this field. The CAML Query as below.

<Query>
 <Where>
    <Or>
		<Membership Type="CurrentUserGroups">
			<FieldRef Name="Group"/>							 
		</Membership>
		<Eq>
		  <FieldRef Name="Group"/>
			<Value Type="Integer">
				<UserID/>
			</Value>
		</Eq>
    </Or>
  </Where>
</Query>

Best Regards,

Dennis

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