文本文件中[* anytext *]的正则表达式。帮助plzz [英] regex for [*anytext*] in a text file. help plzz
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问题描述
我需要在文本文件中找到[* anytext *]的模式匹配。
示例
这是一个包含所有列表的自动电子邮件昨天启动的服务([*昨天*])。请注意,对齐结算的天数将是< b> [* DaysToAlignBilling *]。< / b> < br />< br /> .......
我需要从这个文件中提取所有[* .... *]标签。
任何帮助高度赞赏
解决方案
试试这种模式:@" \ [\ *。*?\ * \]"
这与开始和结束相匹配"[*" " *]"模式并以非贪婪的方式捕捉它们之间的任何角色。这是一个例子:
string test = "这是一封自动发送的电子邮件.. ([* *昨天])。请注意......< b> [* DaysToAlignBilling *]。< / b>" ;
foreach (匹配m Regex.Matches(test,@ " \ [\\ \\ *。*?\ * \]" ))
{
Console.WriteLine(m.Value);
}
Hi, I need to find the pattern match for [*anytext*] in a text file.
example
This is an automated email containing a list of all services activated yesterday ([*Yesterday*]). Please note that the number of days to align billing will be <b>[*DaysToAlignBilling*].</b> <br/><br/>.......
I need to extract all the [*.... *] tags from this file.
Any help highly appreciated解决方案Try this pattern: @"\[\*.*?\*\]"
This matches the opening and closing "[*" "*]" pattern and captures any character in between them in a non-greedy fashion. Here's an example:
string test = "This is an automated email ... ([*Yesterday*]). Please note that ... <b>[*DaysToAlignBilling*].</b>"; foreach (Match m in Regex.Matches(test, @"\[\*.*?\*\]")) { Console.WriteLine(m.Value); }
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