用powershell中的正则表达式替换文本文件的内容 [英] Replace the content of a textfile with a regex in powershell

问题描述

我有一个简单的文本文件，我需要一个 powershell 脚本来替换文件内容的某些部分.

I have a simple textfile and I need a powershell script to replace some parts of the file content.

我当前的脚本如下:

$content = Get-Content -path "Input.json"

$content -Replace '"(\d+),(\d{1,})"', '$1.$2' |  Out-File "output.json"

是否可以像这样在没有内容变量的情况下将其写成一行?

Is it possible to write it in one line without the content variable, like this?

Get-Content -path "Input.json" | ??? -Replace '"(\d+),(\d{1,})"', '$1.$2' |  Out-File "output.json"

我不知道如何在没有 $content 变量的情况下在第二个命令中使用第一个 get-content commandlet 的输出?是否有自动powershell变量

I don't know how I can use the output of the first get-content commandlet in the second command without the $content variable? Is there an automatic powershell variable

是否可以在管道中进行多于一个的替换.

Is it possible to do more replacements than one in a pipeline.

Get-Content -path "Input.json" | ??? -Replace '"(\d+),(\d{1,})"', '$1.$2' | ??? -Replace 'second regex', 'second replacement' |  Out-File "output.json"

推荐答案

是的，您可以在一行中完成，甚至不需要管道，因为 -replace 可以像您一样处理数组希望它这样做(并且您可以链接运算符):

Yes, you can do that in one line and don't even need a pipeline, as -replace works on arrays like you would expect it to do (and you can chain the operator):

(Get-Content Input.json) `
    -replace '"(\d+),(\d{1,})"', '$1.$2' `
    -replace 'second regex', 'second replacement' |
  Out-File output.json

(为了可读性添加了换行符.)

(Line breaks added for readability.)

Get-Content 调用周围的括号是必要的，以防止 -replace 运算符被解释为 Get-Content 的参数.

The parentheses around the Get-Content call are necessary to prevent the -replace operator being interpreted as an argument to Get-Content.

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