为SQl表列设置前缀(最好在主键列上) [英] Setting Prefix for SQl table columns (preferably on primary key column)
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问题描述
我想设计一个员工表,其中employee_id(主键)以序列E0001,E0002开头, E0003 ...
请帮忙...
解决方案
在这里你去:
CREATE TABLE [tbl_SR_employeeInfo](
[employeeName] [nvarchar](359),
[colorHair] [nvarchar](MAX)
)
CREATE TABLE [tbl_SR_employeeInfoIdx](
[Idx] [int] IDENTITY(1,1),
[employeeName] [ nvarchar](359),
[colorHair] [nvarchar](MAX)
)
employeeInfo.txt的内容包含制表符分隔的数据文件示例数据:
originalgriff white
ronbeyer brown
andrekraak black
codehunt red
BULK INSERT [tbl_SR_employeeInfo]
FROM'C:\USERS\SR\employeeInfo_td.txt'
现在转账第一个表数据到第二个表:
INSERT INTO [tbl_SR_employeeInfoIdx]
SELECT [employeeName],[colorHair] FROM [tbl_SR_employeeInfo]
现在,当你去查询后面的表时,使用过滤器为索引字段添加前缀:
SELECT [Idx],[employeeName],[colorHair],LEFT(REPLICATE(' 0',6),6-LEN(Idx))+ CAST([Idx] AS [nvarchar](12))AS [zeropaddedIdx],'N'+ LEFT(REPLICATE('0',6),6-LEN (Idx))+ CAST([Idx] AS [nvarchar](12))AS [concatenationFinal] FROM [cpqa]。[tbl_SR_employeeInfoIdx]
订单更接近要求
Hi,
I want to design an employee table where the employee_id(primary key) starts with sequence E0001, E0002,E0003...
Please help...
解决方案
Here you go:
CREATE TABLE [tbl_SR_employeeInfo]( [employeeName][nvarchar](359), [colorHair][nvarchar](MAX) )
CREATE TABLE [tbl_SR_employeeInfoIdx]( [Idx][int]IDENTITY(1,1), [employeeName][nvarchar](359), [colorHair][nvarchar](MAX) )
Content of employeeInfo.txt a tab-delimited datafile containing example data:
originalgriff white ronbeyer brown andrekraak black codehunt red
BULK INSERT [tbl_SR_employeeInfo] FROM 'C:\USERS\SR\employeeInfo_td.txt'
Now transfer first table data to second table:
INSERT INTO [tbl_SR_employeeInfoIdx] SELECT [employeeName], [colorHair] FROM [tbl_SR_employeeInfo]
Now, when you go to query the later table, prefix the indexed field using a filter:
SELECT [Idx], [employeeName], [colorHair], LEFT(REPLICATE('0', 6), 6-LEN(Idx)) + CAST([Idx] AS [nvarchar](12)) AS [zeropaddedIdx], 'N'+ LEFT(REPLICATE('0', 6), 6-LEN(Idx)) + CAST([Idx] AS [nvarchar](12)) AS [concatenationFinal] FROM [cpqa].[tbl_SR_employeeInfoIdx]
Order as closer to requirement.
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