执行系统命令 [英] Execute System command

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本文介绍了执行系统命令的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

你好朋友。

我的程序必须在Windows的登录屏幕后立即执行。为此我更改了一些注册表值,现在这个程序在启动时启动而不是Explorer.exe

我的程序用户输入他们的用户名和密码,然后登录系统。登录后,我想运行explorer.exe和任务栏并启动菜单,显示给用户。所以我使用这段代码执行系统命令:

hello friends.
my program must be executed immediately after windows's Login screen.for this purpose i changed some registry values and now this program launch on start-up instead of Explorer.exe
in my program users enter their username and password and then login to system. after login, i want to run explorer.exe and taskbar and start menu, appear to user. so i use this code to execute system command:

string cmd = "/C explorer.exe ";
System.Diagnostics.Process.Start("CMD.exe", cmd);





但执行此命令后,只显示我的电脑窗口,并且不显示任务栏和开始菜单。

I如果你能回答我怎么能在执行explorer.exe命令后看到任务栏和启动菜单,我将不胜感激。



but after execute this command, just My Computer window appear and taskbar and start menu not visible.
I would be grateful if you could answer me how can i see taskbar and start menu after execute explorer.exe command.

推荐答案





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Hi,

Check this one

using System.Runtime.InteropServices;


  private void button1_Click(object sender, EventArgs e)
        {
        
            string cmd = "/C explorer.exe ";
            System.Diagnostics.Process.Start("CMD.exe", cmd);
            DisplayStartMenu();
           
        }

        private static void DisplayStartMenu()
        {
            // key down event:
            const byte keyControl = 0x11;
            const byte keyEscape = 0x1B;
            keybd_event(keyControl, 0, 0, UIntPtr.Zero);
            keybd_event(keyEscape, 0, 0, UIntPtr.Zero);

            // key up event:
            const uint KEYEVENTF_KEYUP = 0x02;
            keybd_event(keyControl, 0, KEYEVENTF_KEYUP, UIntPtr.Zero);
            keybd_event(keyEscape, 0, KEYEVENTF_KEYUP, UIntPtr.Zero);
        }

        [DllImport("user32.dll")]
        static extern void keybd_event(byte bVk, byte bScan, uint dwFlags,
           UIntPtr dwExtraInfo);


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