使用左外部联接进行微调查询 [英] Fine tune query with Left Outer Joins

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问题描述

大家好,

我被要求微调一个永远执行的查询。 :(它使用3个巨大的表,每个数据包含12万个数据,查询包含许多左外连接,我认为这会产生巨大的交叉连接。



< pre lang =SQL> SELECT ss。[ID],
ss。[Code],
ss。[center],
dupCheck。[ID],
hdr.ObjectKey,
hdr。[Status],
map.ID
FROM snapshot ss
LEFT OUTER JOIN header hdr ON hdr.Code = ss.center
LEFT OUTER JOIN 映射地图 ON ss.Code = map.Code
LEFT OUTER JOIN
SELECT MIN(id) AS [ID] FROM snapshot WHERE status = ' P' GROUP BY 代码,文件名)dupCheck ON dupCheck。[ID] = ss.ID
WHERE ss.status = ' P'





请给我一些微调的想法.. UNION ALL会有左加入帮助吗?



提前致谢,

解决方案

查看以下查询





  SELECT  MIN(id) AS  [ID] 
INTO #dupCheck
FROM snapshot WHERE 状态= ' P' GROUP BY 代码,文件名

SELECT ss。[ID],
ss。 [代码],
ss。[中心],
dupCheck。[ID],
hdr.ObjectKey,
hdr。[状态],
map.ID
FROM snapshot ss
LEFT OUTER JOIN header hdr ON hdr.Code = ss.center
LEFT OUTER JOIN 映射地图 ON ss.Code = map.Code
LEFT OUTER JOIN #dupCheck dc ON dc。[ID] = ss.ID
WHERE ss.status = ' P'


Hi All,
I am asked to fine tune a query which taking forever to execute. :( .. It uses 3 huge tables, with 12 lakhs data each and the query contanins many left outer joins which I think result in a huge cross join.

SELECT ss.[ID],   
 ss.[Code],  
 ss.[center],  
 dupCheck.[ID],  
 hdr.ObjectKey,
 hdr.[Status],
 map.ID
FROM snapshot ss  
LEFT OUTER JOIN header hdr ON hdr.Code = ss.center  
LEFT OUTER JOIN Mapping map ON ss.Code = map.Code   
LEFT OUTER JOIN 
	(SELECT MIN(id) AS [ID] FROM snapshot WHERE status='P' GROUP BY Code, Filename) dupCheck ON dupCheck.[ID] = ss.ID  
WHERE ss.status='P'



Please give me some ideas to fine tune.. Will UNION ALL with left join help?

Thanks in advance,

解决方案

have a look at following Query


SELECT MIN(id) AS [ID]
INTO #dupCheck
FROM snapshot WHERE status='P' GROUP BY Code, Filename

SELECT ss.[ID],   
 ss.[Code],  
 ss.[center],  
 dupCheck.[ID],  
 hdr.ObjectKey,
 hdr.[Status],
 map.ID
FROM snapshot ss  
LEFT OUTER JOIN header		hdr ON hdr.Code = ss.center  
LEFT OUTER JOIN Mapping		map ON ss.Code = map.Code   
LEFT OUTER JOIN #dupCheck	dc	ON	dc.[ID] = ss.ID  
WHERE ss.status='P'


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